PID算法MATLAB仿真.rar

%qq778132974 clear all; close all; ts=0.001; sys=tf(50,[0.125,7, 0]); dsys=c2d(sys,ts,'z'); [num,den]=tfdata(dsys,'v'); u_1=0.0;u_2=0.0; y_1=0.0;y_2=0.0; x=[0,0,0]'; error_1=0; error_2=0; for k=1:1:1000 time(k)=k*ts; S=2; if S==1 kp=10;ki=0.1;kd=15; rin(k)=1; %Step Signal elseif S==2 kp=10;ki=0.1;kd=15; %Sine Signal rin(k)=0.5*sin(2*pi*k*ts); end du(k)=kp*x(1)+kd*x(2)+ki*x(3); %PID Controller u(k)=u_1+du(k); %Restricting the output of controller if u(k)>=5 u(k)=5; end if u(k)<=-5 u(k)=-5; end %Linear model yout(k)=-den(2)*y_1-den(3)*y_2+num(2)*u_1+num(3)*u_2; error(k)=rin(k)-yout(k); %Return of parameters u_2=u_1;u_1=u(k); y_2=y_1;y_1=yout(k); x(1)=error(k)-error_1; %Calculating P x(2)=error(k)-2*error_1+error_2; %Calculating D x(3)=error(k); %Calculating I error_2=error_1; error_1=error(k); end figure(1); plot(time,rin,'b',time,yout,'r'); xlabel('time(s)'),ylabel('rin,yout'); figure(2); plot(time,error,'r') xlabel('time(s)');ylabel('error');