C 代码 报告调用它的命令行参数args.rar

# include <stdio.h> # include <stdlib.h> # include <time.h> # include "args.h" /******************************************************************************/ int main ( int argc, char *argv[] ) /******************************************************************************/ /* Purpose: ARGS reports on the command line arguments. Discussion: On input, ARGC is the number of command line arguments (including the program name itself), and ARGV is a pointer to an array of pointers, the null-terminated strings that constitute the command line arguments. Thus, if we have invoked a program by: fred 1 alpha 3.7 then on input ARGC is 4, and ARGV --> ARGV(0) --> "fred" ARGV(1) --> "1" ARGV(2) --> "alpha" ARGV(3) --> "3.7" Licensing: This code is distributed under the GNU LGPL license. Modified: 26 April 2007 Author: John Burkardt */ { int i; int VERBOSE = 1; if ( VERBOSE ) { timestamp ( ); printf ( "\n" ); printf ( "ARGS\n" ); printf ( " GCC version %d.%d.%d\n", __GNUC__, __GNUC_MINOR__,__GNUC_PATCHLEVEL__ ); printf ( "\n" ); printf ( " Print the command line arguments of a C program.\n" ); printf ( "\n" ); printf ( " ARGC reports the number of arguments as %d\n", argc ); printf ( "\n" ); } for ( i = 0; i < argc; i++ ) { printf ( " %d \"%s\"\n", i, *argv ); argv++; } /* Terminate. */ if ( VERBOSE ) { printf ( "\n" ); printf ( "ARGS:\n" ); printf ( " Normal end of execution.\n" ); printf ( "\n" ); timestamp ( ); } return 0; }