DES.zip_des_matlab_s盒加密_加密算法_密钥生成

第五次作业——DES 算法

一、源代码

1. 密钥产生部分

function K=make_miyao(miyao)

c_zhh=[57 49 41 33 25 17 9

1 58 50 42 34 26 18

10 2 59 51 43 35 27

19 11 3 60 52 44 36];

d_zhh=[63 55 47 39 31 23 15

end

zhi2=[14, 17, 11, 24, 1, 5, 3, 28, 15, 6, 21, 10,23, 19, 12, 4, 26, 8,

16, 7, 27, 20, 13, 2,41, 52, 31, 37, 47, 55, 30, 40, 51, 45, 33, 48,44,

49, 39, 56, 34, 53, 46, 42, 50, 36, 29, 32];

K=[];

for i=[1:2,9,16]

c=C0(1,1);d=D0(1,1);

for j=1:27

C0(j)=C0(j+1);D0(j)=D0(j+1);

end

for i=[3:8,10:15]

c1=C0(1,1);c2=C0(1,2);d1=D0(1,1);d2=D0(1,2);

for j=1:26

C0(j)=C0(j+2);D0(j)=D0(j+2);

end

C0(27)=c1;D0(27)=d1;C0(28)=c2;D0(28)=d2;

CD=[C0,D0];

for k=1:48

K(i,k)=CD(zhi2(k));

end

4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0

15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13];

S2=[15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10

3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5

0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15

13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9];

1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12];

S4=[7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5 ,11, 12, 4, 15

13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9

10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4

3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14];

S5=[2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9

14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6

4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14

S7=[4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1

13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6

6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12];

S8=[13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7

1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2

7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8