2021/3/7 5
信念度
普适的可比性假设
(A | C) (B | C) ,(A | C) ~ (B | C) ,(A | C) (B | C)中必有一个成立
传递性假设
如果(A | D) (B | D),(B | D) (C | D) ,那么(A | D) (C | D)
基于这两条假设,可以用实值函数P来表示信念度:
P(A | C) > P(B | C)当且仅当(A | C) (B | C)
P(A | C) = P(B | C)当且仅当(A | C) ~ (B | C)
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