数据结构课程设计—— 运动会分数统计

# define LEN sizeof (SC) # include"stdio.h” # include"stdlib.h” Typedef struct scoredetail { int score; Char programer; Char school; }SC; Typedef struct scoredef1 { int score; Char programer; Char school; Struct scoredef1 *next; }SC1; Void input() /*输入函数，完成将键盘输入的学生数据写入磁盘*/ { SC a1; char I; /*结构体变量a1用来存放一个运动员的数据*/ FILE *fp; Clrslr(); /*清屏*/ If (fp=fopen("e:\\file1”, "wb”)= =NULL) {printf("error!\n”);exit(0);} While(i=’1’;i<=(‘m’+’w’-2*’1’)*(‘n’-‘1’+1);i++) /*以循环方式输入每个运动员的数据*/ {printf("\tschool:”); Scanf("%c”,&a1.school); while(a.school<’1’||a.school>’n’) {Printf(“\terror! Input school again.”);scanf(“\%c”,&a1.school);} Printf("\tprogramer:”); Scanf("%c”,&a1.programer); while(a.programer<’1’||a.programer>’m’+’w’) {printf(“\teror! Input programer again.”);scanf(“\%c”,&a1.programer);} Printf("\tscore:”); Scanf("%d”,&a1.score); While(a.score<0) {printf(“\terror! Input score again.”);scanf(“\%d”,&a1.score);} Fwrite(&a1,sizeof(SC),1,fp); } Fclose(fp); } SC1 creat () /*建立链表函数，完成用链表来存放从文件中读取的运动员数据*/ {SC1 *head1,*p1,*p2; FILE *fp; Clrslr(); P1=p2=(SC1*)malloc(LEN); Head1=NULL; If(fp=fopen("e:\\file1”, "rb”))= =NULL) {printf("error!\n”);exit(0);} While(fread(*p1,sizeof(SC),1,fp)!=0) {if(head1= =NULL) head=p1; Else p2->next=p1; P2=p1; P1=(SC1*)malloc(LEN);} Free(p1); P2->next=NULL; Return head1; } SC thirdfifth(SC *p3,char a) /*本函数实现找出运动项目a的前三（五）名的成绩*/ { SC t,a[20],b[5];int i=0,j; While(p3!=NULL) /*通过循环把各个学校的项目a的成绩放在数组a[20]中*/ {if(p3->programmer=a) {a[i]=*p3;i++;} P3=p3->next; } For(i=0;i<5;i++) /*对a[20]中的数进行排序*/ For(j=i+1;j<=20;j++) If(a[i].score<a[j].score) {t=a[i];a[i]=a[j];a[j]=t;} Printf("%d,%d,%d”,a[0].score,a[1].score,a[2].score); /*输出前三名的成绩*/ If(a>=('m'-'1')/2+'1'&&a<'m'+'1'||a>=('w'-‘1’)/2+'m') Printf(“%d,%d”,a[3].score,a[4].score); /*输出第四、五名的成绩*/ For(i=0;i<5;i++) B[i]=a[i]; Return b[5]; } void Athirdfifth() /*本函数实现输出各个项目的前三（五）名的成绩*/ {char I; For(i='1';i<='m'+'w';i++) {printf(“\t The scores of the top 3 or 5 of the programmer %c are：\n”,i); Thirdfifth(head,i); } } Int statistic(int *k,char b) /*本函数实现统计学校b的总成绩*/ {SC a[5];int ,j,s1,s2,s3,s4,s;char i; For(i='1';i<('m'-'1')/2+'1';i++) /*统计学校b男子团体的总分*/ {a[5]=thirdfifth(head,i); For(j=0;j<3;j++) If(a[j].school=b) Switch(j) {case 0:s1+=5;break; Case 1:s1+=3;break; Case 2:s1+=2;break; } } For(i=('m'-'1')/2+'1';i<='m';i++) {a[5]thirdfifth(head,i); For(j=0;j<5;j++) If(a[j].school=b) Switch(j) {case 0:s2+=7;break; Case 1:s2+=5;break; Case 2:s2+=3;break; Case 3:s2+=2;break; Case 4:s2+=1;break; } } For(i='m’+’1';i<('w'-‘1’)/2+'m';i++) /*统计学校b女子团体的总*/ {a[5]=thirdfifth(head,i); For(j=0;j<3;j++) If(a[j].school=b) Switch(j) {case 0:s3+=5;break; Case 1:s3+=3;break; Case 2:s3+=2;break; } } For(i=('w'-‘1’)/2+'m';i<='m'+'w';i++) {a[5]=thirdfifth(head,i); For(j=0;j<5;j++) If(a[j].school=b) Switch(j) {case 0:s4+=7;break; Case 1:s4=5;break; case 2:s4+=3;break; case 3:s4+=2;break; case 4:s4+=1;break; } } *k=s1+s2; Return s=s1+s2+s3+s4; } void Astatistic() /*本函数实现输出各个学校的总分*/ {int sum,k1=0;char I; For(i='1';i<='n';i++) {sum=statistic(&k1;i); Printf(“school\t%cscore\t%d\n”,I,sum) } } void sort() /*本函数实现按学校编号.学校总分.男女团体总分排序输出*/ {struct schoolscore {char school; int score; }ss[20],ssb[20],ssw[20],t; /*ss[20],ssb[20],ssw[20]分别存放各个学校的总分.男生团体总分.女生团体总分*/ int a1=0;char i;int a,j,d; for(i='1',a=0;i<='n';i++,a++) {ss[a].score=statistic(&a1,i); ss[a].school=i; ssb[a].score=a1; ssb[a].school=i; ssw[a].school=ss[a].score-a1; ssw[a].school=i; } a--; for(d=0;d<a;d++) /*对各个学校的总分.男生团体总分.女生团体总分进行排序*/ for(j=d+1;j<a+1;j++) {if(ss[d].score<ss[j].score) {t=ss[d];ss[d]=ss[j];ss[j]=t;} if(ssb[d].score<ssb[j].score) {t=ssb[d];ss[d]=ss[j];ss[j]=t;} if(ssw[d].score<ssw[j].score) {t=ssw[d];ssw[d]=ssw[j];ssw[j]=t;} printf("\tassort by the sum of a school and output the result:\n"); /*输出按学校总分排序的结果*/ for(d=0;d<=a;d++) printf("school\t%cscore\t%d",ss[d].school,ss[d].score); printf("\tassort by the sum of the boys of a school and output the result:\n"); /*输出按学校男生团体总分排序的结果*/ for(d=0;d<a+1;d++) printf("\tschool\t%cboy score\t%d",ssb[d].school,ssb[d].score); printf("\tassort on the sum of the girls of a school and output the result :\n"); /*输出按学校女生团体总分排序的结果*/ for(d=0;d<a+1;d++) printf("\tschool\t%cgirl score\t%d",ssw{d].school.ssw[d].score); } void inquire1() /*本函数实现按学校编号查询学校某个项目的情况*/ {SC a[5];char a1,a2; int i; printf("\tinput the school code you want to inquire\n"); scanf("%c\n",&a1); printf("\tinput the programmer code you want to inquire\n"); scanf("%c\n",&a2); a[5]=thirdfifth(head,a2); /*找出项目a2的前五名*/ for(i=0;i<5;i++) /*通过循环找出学校a1的项目a2的成绩*/ if(a[i].school=a1) break; if(i<3) printf("\tschool\t%c\tprogrammer \t%c\tranking\t%d",a1,a2,i+1); if(i>2&&(a[i].school>=('w'-‘1’)/2+'m'||a[i].school>=('m'-‘1’)/2+'1'&&a[i].school<'m’+1)) printf("\tschool\t%c\tprogrammer\t%c\tranking\t%d".a1,a2.i+1); if(i=6) printf(“\tthe programmer gets no score\n”); } void inquire2() /*本函数实现按项目编号查询取得前三(五)名的学校*/ {SC a[5];char a1;int i; printf("\tinput the programmer code you want to inquire\n"); scanf("%c\n",&a1); a[5]=thirdfifth(head,a1); printf("\tthe top 3 or 5 schools of the programmer are\n"); for(i=0;i<3;i++) printf("%c\t",a[i].school); if(a1>=('m'-‘1’)/2+'1'&&a[i].school<'m’+1||a1>=('w'-‘1’)/2+'m') for(i=3;i<5;i++) printf("%c",a[i].school); } main() {int x,m1,n1,w1;char m,n,w; SC head; head=creat(); /* 将链表的首地址赋给head*/ printf("\tinput the NO. of the school \n"); scanf("%d",&n1); printf("\tinput the NO. of the boy programmer\n"); scanf("%d",&m1); printf(“\tinput the NO. of the girl programmer\n"); scanf(“%d”,&w1); m=(char)m1; /*对m1个学校进行编码*/ n=(char)n1; /*对n1个项目进行编码*/ w=(char)w1; /*对 w1个项目进行编码*/ do {clrscr(); printf("\n\n\n\n\n\t\tplayer score management system\n"); printf("\t\t***************************************************************************************