python井字游戏源码

​ 以下是一个简单的Python井字游戏的源码实现： # 定义棋盘大小 board = [' ' for _ in range(9)] def print_board(): print() print(board[0] + ' | ' + board[1] + ' | ' + board[2]) print('---------') print(board[3] + ' | ' + board[4] + ' | ' + board[5]) print('---------') print(board[6] + ' | ' + board[7] + ' | ' + board[8]) print() def is_winner(player): # 横向 if (board[0] == player and board[1] == player and board[2] == player) or \ (board[3] == player and board[4] == player and board[5] == player) or \ (board[6] == player and board[7] == player and board[8] == player) or \ # 纵向 (board[0] == player and board[3] == player and board[6] == player) or \ (board[1] == player and board[4] == player and board[7] == player) or \ (board[2] == player and board[5] == player and board[8] == player) or \ # 斜向 (board[0] == player and board[4] == player and board[8] == player) or \ (board[2] == player and board[4] == player and board[6] == player): return True else: return False def is_board_full(): if ' ' in board: return False else: return True def play_game(): current_player = 'X' while True: print_board() position = int(input("轮到'" + current_player + "'玩家，请输入位置(1-9): ")) if board[position - 1] == ' ': board[position - 1] = current_player else: print("该位置已经被占据，请重新输入。") continue if is_winner(current_player): print_board() print("玩家 '" + current_player + "' 赢了！") break elif is_board_full(): print_board() print("平局！") break # 交换玩家 if current_player == 'X': current_player = 'O' else: current_player = 'X' play_game() 玩家通过输入位置来下棋，按照1-9的顺序依次对应棋盘上的位置。在每次下棋之后，程序会判断当前玩家是否获胜或者棋盘是否已满，如果是则游戏结束，否则交换玩家继续下棋。 ​