关于在关于在labelme批量转化批量转化json文件时文件时PermissionError: [Errno
13] Permission denied: ‘F:/zkx/list_path[i]’的解决的解决
首先我要解释一下,很多时候出现这个问题,并不是你的文件有毛病,很可能是你代码读取的路径不对,这就要追究到代码本
身。批量转化可以在json_to_dataset文件里直接运行代码实现。这个思路还要感谢我的一个师兄。
代码如下:
import argparse
import base64
import json
import os
import os.path as osp
import imgviz
import PIL.Image
from labelme.logger import logger
from labelme import utils
import cv2
from math import *
import numpy as np
import random
import rotate
def main():
list_path = os.listdir('F:/zkx')
for i in range(0, len(list_path)):
logger.warning('This script is aimed to demonstrate how to convert the'
'JSON file to a single image dataset, and not to handle'
'multiple JSON files to generate a real-use dataset.')
parser = argparse.ArgumentParser()
parser.add_argument('--json_file')
parser.add_argument('-o', '--out', default=None)
args = parser.parse_args()
json_file = 'F:/zkx/' + list_path[i] print(list_path[i])
if args.out is None:
out_dir = osp.basename(json_file).replace('.', '_') # 返回文件名
out_dir = osp.join(osp.dirname(json_file), out_dir) # 把目录和文件名合成一个路径
else:
out_dir = args.out
if not osp.exists(out_dir):
os.mkdir(out_dir) # 用于以数字权限模式创建目录
data = json.load(open(json_file))
imageData = data.get('imageData')
if not imageData:
imagePath = os.path.join(os.path.dirname(json_file), data['imagePath']) # os.path.dirname返回文件路径
with open(imagePath, 'rb') as f:
imageData = f.read()
imageData = base64.b64encode(imageData).decode('utf-8')
img = utils.img_b64_to_arr(imageData)
label_name_to_value = {'_background_': 0}
for shape in sorted(data['shapes'], key=lambda x: x['label']):
label_name = shape['label'] if label_name in label_name_to_value:
label_value = label_name_to_value[label_name] else:
label_value = len(label_name_to_value)
label_name_to_value[label_name] = label_value
lbl, _ = utils.shapes_to_label(
img.shape, data['shapes'], label_name_to_value
)
label_names = [None] * (max(label_name_to_value.values()) + 1)
for name, value in label_name_to_value.items():
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