python实现简单井字棋小游戏
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2020-12-20
09:44:32
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python实现简单井字棋小游戏实现简单井字棋小游戏
用python实现的一个井字棋游戏，供大家参考，具体内容如下
#Tic-Tac-Toe 井字棋游戏
#全局常量
X="X"
O="O"
EMPTY=" "
#询问是否继续
def ask_yes_no(question):
response=None;
while response not in("y","n"):
response=input(question).lower()
return response
#输入位置数字
def ask_number(question ,low,high):
response=None
while response not in range(low,high):
response=int(input(question))
return response
#询问谁先走，先走方为X,后走方为O
#函数返回计算机方，玩家的角色代号
def pieces():
go_first=ask_yes_no("玩家你是否先走（y/n):")
if go_first=="y":
print("玩家你先走.")
human=X
computer=O
else:
print("计算机先走.")
computer=X
human=O
return computer,human
#产生新的棋盘
def new_board():
board=[] for square in range(9):
board.append(EMPTY)
return board
#显示棋盘
def display_board(board):
board2=board[:] for i in range(len(board)):
if board[i]==EMPTY:
board2[i]=i
print(" ",board2[0],"|",board2[1],"|",board2[2])
print(" ","----------")
print(" ",board2[3],"|",board2[4],"|",board2[5])
print(" ", "----------")
print(" ",board2[6],"|",board2[7],"|",board2[8],"")
#产生可以合法走棋位置序列（也就是还未下过子位置）
def legal_moves(board):
moves=[] for square in range(9):
if board[square]==EMPTY:
moves.append(square)
return moves
#判断输赢
def winner(board):
# 所有赢得可能情况，例如（0,1,2）就是第一行，（0,4,8,），（2,4,6）就是对角线
WAYS_TO_WIN=((0,1,2,),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6))
for row in WAYS_TO_WIN:
if board[row[0]]==board[row[1]]==board[row[2]]!=EMPTY:
winner=board[row[0]] return winner
#棋盘没有空位置
if EMPTY not in board:
return "TIE"
return False
#人走棋
def human_move (board,human):
legal =legal_moves(board)
move =None
while move not in legal:
move=ask_number("你走那个位置？（0-8）：",0,9)
if move not in legal:
print("此位置已经落过子了")
#print("Fine...")
return move
#计算机走棋
def computer_move(board,computer ,human):
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