javascript实现通过拼音首字母快速选择下拉列表
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2020-10-30
10:57:14
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javascript实现通过拼音首字母快速选择下拉列表实现通过拼音首字母快速选择下拉列表
比如，某选项的拼音首字母为"a",只要按下键盘上的"a"，就可以快速选择该项。如何解决重音字 和兼容ff.ff下怎
呢得到asc呢，忘高手指教
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>下拉列表快速选择</title>
<script type="text/javascript" language="JavaScript">
// 获取拼音首字母
function getPinYin(c) {
execScript("tmp=asc(\""+c+"\")", "vbscript");
tmp = 65536 + tmp;
if(tmp>=45217 && tmp<=45252) return "A";
if(tmp>=45253 && tmp<=45760) return "B";
if(tmp>=45761 && tmp<=46317) return "C";
if(tmp>=46318 && tmp<=46825) return "D";
if(tmp>=46826 && tmp<=47009) return "E";
if(tmp>=47010 && tmp<=47296) return "F";
if((tmp>=47297 && tmp<=47613) || (tmp == 63193)) return "G";
if(tmp>=47614 && tmp<=48118) return "H";
if(tmp>=48119 && tmp<=49061) return "J";
if(tmp>=49062 && tmp<=49323) return "K";
if(tmp>=49324 && tmp<=49895) return "L";
if(tmp>=49896 && tmp<=50370) return "M";
if(tmp>=50371 && tmp<=50613) return "N";
if(tmp>=50614 && tmp<=50621) return "O";
if(tmp>=50622 && tmp<=50905) return "P";
if(tmp>=50906 && tmp<=51386) return "Q";
if(tmp>=51387 && tmp<=51445) return "R";
if(tmp>=51446 && tmp<=52217) return "S";
if(tmp>=52218 && tmp<=52697) return "T";
if(tmp>=52698 && tmp<=52979) return "W";
if(tmp>=52980 && tmp<=53688) return "X";
if(tmp>=53689 && tmp<=54480) return "Y";
if(tmp>=54481 && tmp<=62289) return "Z";
return c.charAt(0);
}
// select helper
SelectHelper = new function() {
// 初始化
this.init = function() {
document.attachEvent("onkeypress", function() {
var elm = event.srcElement;
if (elm.tagName == "SELECT"
&& elm.className.indexOf("SelectHelper") == -1) {
elm.className += "SelectHelper";
elm.attachEvent("onkeypress", SelectHelper.getNextKeyItem);
elm.fireEvent("onkeypress", event);
}
});
}
// 获取选项文本的首字符
function getItemKeyChar(option) {
return option.text.charAt(0).toUpperCase();
}
// 查找并选中匹配的选项
this.getNextKeyItem = function() {
var elm = event.srcElement;
var index = elm.selectedIndex + 1;
do {
if (index == elm.length) index = 0;
if (index == elm.selectedIndex) return false; // 未找到匹配的选项，则退出
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