怎么把php查询到的值显示到下拉框中_course

想在把查询到的值显示在 下拉框 中 这个值只有上 中 下 三种 我加个 <option value="<?php echo $rs;?>"><?php echo $rs;?></option> 但是这

PHP网站下拉框选中后点击搜索问题，求帮忙_course

<div class="search"> <form id="form1" name="form1" method="get" action=""> <select name="lx" id="lx"

使用PHP在查询结果中填充下拉列表_course

<div class="post-text" itemprop="text"> <p>The code should open all the rows of <code>gamename</code> column of <code>games</code> table and put 1700 rows into drop down menu, but it only displays a blank dropdown with 1700 rows.</p> <pre><code>// Connect to server and select database. mysql_connect("$host", "$username", "$password") or die(mysql_error()); mysql_select_db("$db_name") or die(mysql_error()); $i=0; $result = mysql_query("SELECT gamename FROM games"); $storeArray = Array(); echo '&lt;select name="game" style="width: 400px"&gt;'; while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $storeArray[] = $row[i]; echo "&lt;option&gt;".$storeArray[i]."&lt;/option&gt;"; $i= $i+1; } ?&gt; &lt;/select&gt; </code></pre> </div>

PHP怎样选择下拉菜单就搜索数据库把值显示到文本框？_course

选择下拉菜单： <select name="sort" class="tables" id="sort" > <option value="N">- - - -</option> <option va

如何使用PHP上的输入搜索下拉列表_course

<div class="post-text" itemprop="text"> <p>hope all be will. I face to like this problem anyone can help me. I get the value of dropdown and I put it to input, but I am unable to search it. I used from jQuery to get the value from bootstrap dropdown to give for input.</p> <pre><code> &lt;!-- HTML Code With Form --&gt; &lt;!-- Basic dropdown --&gt; &lt;form method="post" enctype="multipart/form-data" action="team.php" class="form-inline active-purple-3 active-purple-4" style="width:400px; margin-top:-50px; margin-left:125px; "&gt; &lt;button id="sb" class="btn btn-primary dropdown-toggle mr-4" type="button" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false" style="margin-top:20px; margin-left:-140px;"&gt;Search By&lt;/button&gt; &lt;div class="dropdown-menu" id="dm" style="margin-left:89px; margin- top:-963px;"&gt; &lt;a class="dropdown-item" id="dl" href="#" value="ID"&gt;BY ID&lt;/a&gt; &lt;a class="dropdown-item" id="dl" href="#" value="Name"&gt;Name&lt;/a&gt; &lt;a class="dropdown-item" id="dl" href="#" value="Positon"&gt;Position&lt;/a&gt; &lt;/div&gt; &lt;input type='hidden' name='thenumbers'&gt; &lt;!-- Basic dropdown --&gt; &lt;!-- Search form --&gt; &lt;i class="fa fa-search" aria-hidden="true" style="margin-top:15px;"&gt;&lt;/i&gt; &lt;input name="txtSearch" class="form-control form-control-sm ml-3 w-75" id="in" type="text" placeholder="Search" style=" margin-top:15px; border- radius:5px 5px 5px 5px;" aria-label="Search"&gt; &lt;button type="Submit" name="searchrec" class="btn btn-primary" style="margin-left:365px; margin-top:-55px;"&gt;Search&lt;/button&gt; &lt;/form&gt; &lt;!-- jQuery Code --&gt; &lt;script&gt; $(document).ready(function(){ $('#dm a').on('click', function(){ $('#sb').text($(this).text()); }); }); &lt;/script&gt; &lt;script&gt; $(function(){ //Listen for a click on any of the dropdown items $("#dm a").click(function(){ //Get the value var value = $(this).text(); //Put the retrieved value into the hidden input $("input[name='thenumbers']").val(value); }); }); &lt;/script&gt; &lt;!-- jQuery Code End --&gt; &lt;!-- PHP Code --&gt; &lt;?php include "Config.php"; if(isset($_POST['searchrec'])) { $txtSearch=$_POST['txtSearch']; $column=$_POST['thenumbers']; if($column == "BY ID") { $query1="SELECT * FROM ourteam WHERE id LIKE '%$txtSearch%'"; $result1=mysqli_query($db,$query1); $count=mysqli_num_rows($result1); if($count == 0) { }else{ while($rowr=mysqli_fetch_array($result1)) { $id=$rowr['id']; $name=$rowr['name']; echo "&lt;script&gt;alert($name);&lt;/script&gt;"; } } </code></pre> <p>This PHP code is just for ID and I used elesif statement also for other entities. </p> </div>