![](https://csdnimg.cn/release/download_crawler_static/86378234/bg2.jpg)
输入:a=[-2 0 1 -1 3] b=[1 2 0 -1 0]
输出:output sequence =
-2 -4 1 3 1 5 1 -3 0
(3)思考:如何计算有限长连续函数的卷积?
(4)实验:
代码:
clear;
x = -1 :0.01: 1;
fx = x; %函数f(x)=x,自变量范围 -1<=x<=1
x = 0 :0.01: 1;
gx = x+1; %函数g(x)=x+1, 自变量范围 0<=x<=1
yx = conv(fx, gx); % 进行卷积计算
x=-1:0.01:2; %卷积结果变量范围为(原函数自变量最小值)~(两原函数
自变量最大值相加)
plot(x,yx);
结果:
Time index n
0 1 2 3 4 5 6 7 8
Amplitude
-4
-3
-2
-1
0
1
2
3
4
5
-1 -0.5 0 0.5 1 1.5 2
-100
-80
-60
-40
-20
0
20
40
60
80
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