![](https://csdnimg.cn/release/download_crawler_static/88201389/bg5.jpg)
8. (NOIP9)设全集E={1,2,3,4,5},集合A={1,4},B={1,2,
A) 空集
5},C={2,4},则集合(A ∩B)∪~C 为(E)
。
B) {1} C) {3,5}
D){1,5} E) {1,3,5}
1、(NOIP10)设全集I = {a,b,c,d,e,f,g},
A. {a, b, c, d} B. {a, b, d, e}
C. {b, d, e
集合A = {a,b,c},B = {b,d,e},C = {e,f,g},
那么集合(A-B)∪(~C-B)为( A ).
} D. {b, c, d, e} E. {d, f, g}