MATLAB条形码识别程序，里面包含M程序，执行所需图片，可直接执行，对于研究条形码识别的有非常好的帮助

%function code = barcode(pic) %条形码识别 close all check_left = [13,25,19,61,35,49,47,59,55,11;... %左边数据编码，奇 39,51,27,33,29,57, 5,17, 9,23]; %左边数据编码，偶 check_right = [114,102,108,66,92,78,80,68,72,116]; %右边数据编码 first_num = [31,20,18,17,12,6,3,10,9,5]; %第一位数据编码 bar = imread('008.bmp'); %读输入条形码图片 bar_Gray = rgb2gray(bar); %将RGB图片转换灰度图 %imshow(bar_Gray) % for i=1:m %对图像进行二值化处理 % for j=1:n % if bar_Gray(i,j)>150 %选择适当的阈值进行二值化处理 % bar_10(i,j) = 1; % else % bar_10(i,j) = 0; % end % end % end [a_hist x] = imhist(bar_Gray); hist_max = []; if a_hist(1)>a_hist(2) hist_max = [hist_max 1]; end x = max(x); for i=2:x if a_hist(i)>a_hist(i-1) && a_hist(i)>a_hist(i+1) hist_max = [hist_max i]; end end if a_hist(x)<a_hist(x+1) hist_max = [hist_max x+1]; end [m,n] = size(hist_max); k = 0; max_1 = 0; max_2 = 0; for i=1:n if k<a_hist(hist_max(i)) k = a_hist(hist_max(i)); max_1 = hist_max(i); end end temp = a_hist(max_1); a_hist(max_1) = 0; k = 0; for i=1:n if k<a_hist(hist_max(i)) k = a_hist(hist_max(i)); max_2 = hist_max(i); end end a_hist(max_1) = temp; if max_1>max_2 k = max_1; max_1 = max_2; max_2 = k; end T = max_1; k = a_hist(max_1); for i=max_1:max_2 if k>a_hist(i) k = a_hist(i); T = i; end end [m,n] = size(bar_Gray); %求灰度图的大小 for i=1:m %对图像进行二值化处理 for j=1:n if bar_Gray(i,j)>T %选择适当的阈值进行二值化处理 bar_10(i,j) = 1; else bar_10(i,j) = 0; end end end %imshow(bar_10); l = 0; %检测59根条形码 for i=1:m k = 1; l = l+1; for j=1:n-1 if bar_10(i,j)~=bar_10(i,j+1) %比较同一行相邻两点的颜色是否一致 %bar_x(l,k) = i; bar_y(l,k) = j; %记录转折点的纵坐标 k = k+1; %准备记录下一个数据点 end if k>61 %点数大于60，该行应该删掉 l = l-1; break end end if k<61 %点数小于60，该行应该删掉 l = l-1; end end [m,n] = size(bar_y); if m<=1 %查看条形码是否有效 code = '0'; fprintf(1,'GameOver!\n'); return end for i=1:m %计算每根条形码的宽度 for j=1:n-1 bar_num(i,j) = bar_y(i,j+1) - bar_y(i,j); if bar_num(i,j)<0 bar_num(i,j) = 0; end end end bar_sum = sum(bar_num)/m; %求每根条形码宽度的平均值 k = 0; for i=1:59 %计算59根条形码的总宽度 k = k + bar_sum(i); end k = k/95; %计算单位条形码的宽度 for i=1:59 %计算每根条形码所占位数 bar_int(i) = round(bar_sum(i)/k); end k = 1; for i=1:59 %将条形码转换成二进制数 if rem(i,2) for j=1:bar_int(i) %黑色条用1表示 bar_01(k) = 1; k = k+1; end else for j=1:bar_int(i) %白色条用0表示 bar_01(k) = 0; k = k+1; end end end if ((bar_01(1)&&~bar_01(2)&&bar_01(3))... %判断起始符是否正确 &&(~bar_01(46)&&bar_01(47)&&~bar_01(48)&&bar_01(49)&&~bar_01(50))... %判断中间分隔符是否正确 &&(bar_01(95)&&~bar_01(94)&&bar_01(93))) %判断终止符是否正确 l = 1; for i=1:6 %将左侧42位二进制数转换为十进制数 bar_left(l) = 0; for k=1:7 bar_left(l) = bar_left(l)+bar_01(7*(i-1)+k+3)*(2^(7-k)); end l = l+1; end l = 1; for i=1:6 %将右侧42位二进制数转换为十进制数 bar_right(l) = 0; for k=1:7 bar_right(l) = bar_right(l)+bar_01(7*(i+6)+k+1)*(2^(7-k)); k = k-1; end l = l+1; end end num_bar = ''; num_first = 0; first = 2; for i=1:6 %从左边数据编码表中查出条形码编码数字 for j=0:1 for k=0:9 if bar_left(i)==check_left(j+1,k+1) num_bar = strcat(num_bar , num2str(k)); switch first %记录左边数据的奇偶顺序 case 2 first = j; break; case 1 num_first = num_first + j*(2^(6-i)); break; case 0 num_first = num_first + ~j*(2^(6-i)); break; otherwise break; end end end end end for i=1:6 %从右边数据编码表中查出条形码编码数字 for j=0:9 if bar_right(i)==check_right(j+1) num_bar = strcat(num_bar , num2str(j)); end end end for i=0:9 %从第一位数据编码表中查出第一位数字 if num_first==first_num(i+1) num_bar = strcat(num2str(i) , num_bar); break; end end if numel(num_bar)~=13 fprintf(1,'Please Turn It Around!\n'); return end check_code = 0; for i=1:12 %计算校验码 if rem(i,2) check_code = check_code + str2num(num_bar(i)); else check_code = check_code + str2num(num_bar(i))*3; end end check_code = rem(check_code,10); if check_code>0 check_code = 10 - check_code; end if check_code==str2num(num_bar(13)) %判断校验码是否正确 code = num_bar else fprintf(1,'Please Turn It Around!\n'); return end