python 实现画爱心源码

import matplotlib.pyplot as plt import seaborn import numpy l = numpy.arange(0, 4, 0.01) L = 1.0 / l theta = numpy.arange(-4, 4, 0.01) o = 3.0 * numpy.cos(theta) O = 3.0 * numpy.sin(theta) v = numpy.arange(-4, 4, 0.01) V = numpy.abs(-2.0 * v) e = numpy.arange(-3, 3, 0.01) E = -1.0 * numpy.abs(numpy.sin(e)) y = numpy.arange(-10, 10, 0.01) Y = numpy.log2(numpy.abs(y)) u = numpy.arange(-4, 4, 0.01) U = 2.0 * u ** 2 points = [] for heartY in numpy.linspace(-100, 100, 500): for heartX in numpy.linspace(-100, 100, 500): if ((heartX*0.03)**2+(heartY*0.03)**2-1)**3-(heartX*0.03)**2*(heartY*0.03)**3 <= 0: points.append({"x": heartX, "y": heartY}) heart_x = list(map(lambda point: point["x"], points)) heart_y = list(map(lambda point: point["y"], points)) fig = plt.figure(figsize=(13, 7)) ax_L = fig.add_subplot(2, 4, 1) ax_O = fig.add_subplot(2, 4, 2) ax_V = fig.add_subplot(2, 4, 3) ax_E = fig.add_subplot(2, 4, 4) ax_Y = fig.add_subplot(2, 4, 5) ax_O_2 = fig.add_subplot(2, 4, 6) ax_U = fig.add_subplot(2, 4, 7) ax_heart = fig.add_subplot(2, 4, 8) plt.plot(colos='tomato') ax_L.plot(l, L) ax_O.plot(o, O) ax_V.plot(v, V) ax_E.plot(E, e) ax_Y.plot(y, Y) ax_Y.axis([-10.0, 10.0, -10.0, 5.0]) ax_O_2.plot(o, O) ax_U.plot(u, U) ax_heart.scatter(heart_x, heart_y, s=10, alpha=0.5) seaborn.set_style('whitegrid') plt.show()