算法设计第四章例子

void mian { static int sum 2; int m 2; int i j n; cout<<"请输入n的值:"; cin>>n; cout<<m; for i 2; i< n; i++ { for j i 1; j<i; j++ m+ 2 power j ; cout<<"+"<<m; sum+ m; } cout<<" "<<sum; }">void mian { static int sum 2; int m 2; int i j n; cout<<"请输入n的值:"; cin>>n; cout<<m; for i 2; i< n; i++ { for j i 1; j<i; j++ m+ 2 power j ; cout<<"+"<<m; sum+ m; } cout<<" "<& [更多]

算法设计第三章实例

void main { int i x y z c a p[6] {50 20 10 5 2 1} s[6]; cout<<"请输入商品价格:"<<endl; cin>>x; cout<<"付款金额:"<<endl; cin>>y; z y x; if z 0 cout<<"找零:0"<<endl; else { for i 0;i<6;i++ { c z p[i]; s[i] c; z z p[i] c; } cout<<"找零:"<<endl; for i 0;i<6;i++ { cout<<p[i]<<" "<<s[i]<<endl; } } }">void main { int i x y z c a p[6] {50 20 10 5 2 1} s[6]; cout<<"请输入商品价格:"<<endl; cin>>x; cout<<"付款金额:"<<endl; cin>>y; z y x; if z 0 cout<<"找零:0"<<endl; else { for i 0;i<6;i++ [更多]

C++矩阵转置实现

程序写的比较简单，是用C++实现的，可运行成功。