#include <iostream>
using namespace std;
bool leap(int a)
{
return ((a % 4 == 0 && a % 100 != 0) || (a % 400 == 0)) ;
}
int total(int year, int month, int day) /*自定义函数 number() 计算输入日期距2011年1月1日共有多少天*/
{
int sum = 0, i, j;
int a[12] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; /*数组a存放平年每月的天数*/
for (j = 2011; j < year; j++){
if (leap(j))
sum += 366;
else
sum += 365;
}
for(i=1;i<month;i++){
sum+=a[i-1];
if(i==2&&leap(year)){
sum+=1;
}
}
sum += day;
return sum;
}
int main(){
int year, month, day, n;
cin >> year >> month >> day;
n = total(year, month, day);
if ((n % 5) < 4 && (n % 5) > 0)
cout << "打渔" << endl;
else
cout << "晒网" << endl;
return 0;
}