raw2bmp.rar_raw2bmp_visual c

#include <stdio.h> #include <windows.h> void main() //void 也可以不要, 想想为什么 { FILE *fp=fopen("d:\\lena.raw","rb"); //打开文件lena.raw if(fp==NULL) { printf("can not open lena.raw\n"); return; } unsigned char *image[1000];//image[i]是一个指针 for(int i=0;i<512;i++) { image[i]=new unsigned char[512]; //申请512字节的内存空间, 把起始地址赋给image[i]; fread(image[i],1,512, fp); } fclose(fp); //可以考虑在此处加入图象处理函数 FILE *fp1=fopen("d:\\new.bmp","wb"); if(fp1==NULL){ printf("can not open new.bmp"); return; } int imageW=512; int imageH=512; int storeW=imageW; if (storeW%4!=0) storeW+=(4-storeW%4); BITMAPFILEHEADER bh; bh.bfType = ((WORD) ('M' << 8) | 'B'); // "BM" bh.bfReserved1=0; bh.bfReserved2=0; bh.bfSize=sizeof(BITMAPFILEHEADER)+sizeof(BITMAPINFOHEADER)+sizeof(RGBQUAD)*256 +storeW*imageH;//注意此处用storeW; bh.bfOffBits=sizeof(BITMAPFILEHEADER)+sizeof(BITMAPINFOHEADER)+sizeof(RGBQUAD)*256; BITMAPINFOHEADER bInfo; bInfo.biSize=sizeof(BITMAPINFOHEADER); bInfo.biWidth=imageW; bInfo.biHeight=imageH; bInfo.biPlanes=1; bInfo.biBitCount=8; bInfo.biCompression=BI_RGB; bInfo.biSizeImage=storeW*imageH; bInfo.biXPelsPerMeter=0; //0是一种简化问题的处理方法 bInfo.biYPelsPerMeter=0; bInfo.biClrUsed=256; bInfo.biClrImportant=0; fwrite(&bh,sizeof(BITMAPFILEHEADER),1,fp1); fwrite(&bInfo,sizeof(BITMAPINFOHEADER),1,fp1); RGBQUAD rgb; rgb.rgbReserved=0; for(i=0;i<256;i++) { rgb.rgbBlue=rgb.rgbRed=rgb.rgbGreen=i; fwrite(&rgb,sizeof(RGBQUAD),1,fp1); } for(i=0;i<512;i++) { fwrite(image[511-i],1,512, fp1); } fclose(fp1);//只有执行完fclose(fp1), 操作系统才会把所有数据写入new.raw, 否则，　有可能还在缓存中 }