this_one_is_for_random_values.rar_(BTS)_BTS_GSM_One Three One

% Computer Man Collage For computer studies % % Telecommunication Department % % Project Name : Modern techniques for location base services % % Submitted by : % % Abubaker Mohamed Ibrahim 2005-06052 % % Khalid Waleed Mohamed 2005-06046 % % Supervisor : % % Co-supervisor % % Project Thesis Submitted in Partial Fulfillment For the Degree of % BSC.(HON)IN Telecommunication Engineering Department% % At Computer Man Collage for Computer Studies % % Observed Time Difference (OTD) % % Real Time Difference (RTD) % % Geometric Time Difference (GTD) % m = 1 ; %m is the number of the mobile in the network% BTS = 3; % BTS is the number of the BTS in the network% Time_A = 100:125 ; index = randperm(26) ; Time_A = 10^-6*Time_A(index); Mx_position = round(70*(rand(1,m))); My_position = round(70*(rand(1,m))); Bx_position = [ 10 90 50 ]; By_position = [ 20 20 90 ]; plot(Bx_position,By_position,'or'); hold on grid axis([0 100 0 100]); BTS_x = 2+Bx_position; BTS_y = 2+By_position; text(BTS_x,BTS_y,'BTS'); plot(Mx_position,My_position,'ms'); hold on grid MS_x= 2+Mx_position; MS_y= 2+My_position; text(MS_x,MS_y,'ms'); grid %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %______________________________________________ % First Hyberbol between BTS1 and BTS3 % d3 - d1 = 3*10^5*(t3 - t1) B = randperm(26); DistanceM_3_1 = 3*10^5*(abs(Time_A(B(1))-Time_A(B(2)))); % 2g = Distance between BTS1 & BTS3. g = sqrt((Bx_position(1)-Bx_position(3))^2+(By_position(1)-By_position(3))^2)/2; % 2a = 2g - (d3-d1) a1 = (2*g - DistanceM_3_1)/2; % b = sqrt(g^2 - a^2) b1 = sqrt(g^2 - a1^2); % x^2/b1^2 - y^2/a1^2 = 1; % First = solve('x^2/a^2 - y^2/b^2 = 1'); %__________________________________________ %Second Hyberbol Between BTS2 and BTS3 % d3 - d2 = 3*10^5*(t3 - t2) B = randperm(26); DistanceM_3_2 = 3*10^5*(abs(Time_A(B(1))-Time_A(B(2)))); % 2g = Distance between BTS2 & BTS3. g2 = sqrt((Bx_position(2)-Bx_position(3))^2+(By_position(2)-By_position(3))^2)/2; % 2a = 2g - (d3-d2)g1 a2 = (2*g2 - DistanceM_3_2)/2; % b = sqrt(g^2 - a^2) b2 = sqrt(g2^2 - a2^2); % x^2/b2^2- y^/a2^=1 ; %solve x^2/b2^2- y^/a2^=1 ;