#include<stdio.h>
void getti(int a,int y,int z);
int i; /*最后需要分出的重量*/
void main()
{
int a,y,z;
clrscr();
puts("***************************************************************");
puts("* This program is to solve Problem of Poisson Beer Division. *");
puts("* The Problem is as follows: Someone has a bottle of 12 pints *");
puts("* beer. He wants to get 6 pints, but he does not has a bottle *");
puts("* of 6 pints. He only has a bottle of 8 pints and a bottle of *");
puts("* 5 pints. So how can he get 6 pints? *");
puts("***************************************************************");
printf(" >> Input Full bottle a,Empty b,c, and Get volumes:\n"); /*a 满瓶的容量 y:第一个空瓶的容量 z:第二个空瓶的容量*/
printf(" >> ");
scanf("%d%d%d%d",&a,&y,&z,&i);
getti(a,y,z); /*按a -> y -> z -> a的操作步骤*/
/*getti(a,z,y); /*按a -> z -> y -> a的步骤*/
printf("\n Press any key to quit...");
getch();
}
void getti(int a,int y,int z) /*a:满瓶的容量 y:第一个空瓶的容量 z:第二个空瓶的容量*/
{
int b=0,c=0,j=0; /* b:第一瓶实际的重量 c:第二瓶实际的重量 j: 倒的步数*/
puts(" >> The division steps are as follows.\n");
printf(" Bottle: a<%d> b<%d> c<%d>\n",a,y,z);
printf("-----------------------------\n");
printf(" Step No.|\n");
printf(" <%d> | %4d %4d %4d\n",j++,a,b,c);
while(a!=i||b!=i&&c!=i) /*当满瓶!=i或另两瓶都!=i*/
{
if(!b)
{ a-=y; b=y;} /*如果第一瓶为空，则将满瓶倒入第一瓶中*/
else if(c==z)
{ a+=z; c=0;} /*如果第二瓶满，则将第二瓶倒入满瓶中*/
else if(b>z-c) /*如果第一瓶的重量>第二瓶的剩余空间*/
{ b-=(z-c);c=z;} /*则将装满第二瓶，第一瓶中保留剩余部分*/
else{ c+=b; b=0;} /*否则，将第一瓶全部倒入第二瓶中*/
printf(" <%d> | %4d %4d %4d\n",j++,a,b,c);
}
printf("-----------------------------\n");
}
