# include <fstream.h>
# include <string.h>
# include <stdio.h>
char wenjian_read[80];
char wenjian_read_buffer[1048576];
char buffer1[255];
char wenjian_write[80];
char wenjian_write_buffer[1048576];
char buffer2[2048];
char encrypt[9]={0x87,0x25,0xDD,0xD9,0x43,0xC7,0x24,0xDD,00};
char table1[64],table2[64],table3[64],table4[64];
unsigned long int filelong1,filelong2,filelong=0;
short int i,i1,i2,over=0,b=3 ;//b=1是加密,b=2是脱密。
int j,j1;//函数中使用
char a ;
char subkey[16][48] ;//存放密钥。
short int b5,b4,b3,b2,b1,b0;//S盒转换时专用。
char s_box_bit[8][2][2][2][2][2][2][4];
//密钥置换表
char encrypt_ip_table1[56] = {
57, 49, 41, 33, 25, 17, 9,
1, 58, 50, 42, 34, 26, 18,
10, 2, 59, 51, 43, 35, 27,
19, 11, 3, 60, 52, 44, 36,
63, 55, 47, 39, 31, 23, 15,
7, 62, 54, 46, 38, 30, 22,
14, 6, 61, 53, 45, 37, 29,
21, 13, 5, 28, 20, 12, 4};
char encrypt_ip_table2[48] = {
14, 17, 11, 24, 1, 5,
3, 28, 15, 6, 21, 10,
23, 19, 12, 4, 26, 8,
16, 7, 27, 20, 13, 2,
41, 52, 31, 37, 47, 55,
30, 40, 51, 45, 33, 48,
44, 49, 39, 56, 34, 53,
46, 42, 50, 36, 29, 32
};
char s_box_byte[512] = {
// S1
14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7,
0, 15, 7, 4, 14, 2, 13, 1, 10, 6, 12, 11, 9, 5, 3, 8,
4, 1, 14, 8, 13, 6, 2, 11, 15, 12, 9, 7, 3, 10, 5, 0,
15, 12, 8, 2, 4, 9, 1, 7, 5, 11, 3, 14, 10, 0, 6, 13,
// S2
15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10,
3, 13, 4, 7, 15, 2, 8, 14, 12, 0, 1, 10, 6, 9, 11, 5,
0, 14, 7, 11, 10, 4, 13, 1, 5, 8, 12, 6, 9, 3, 2, 15,
13, 8, 10, 1, 3, 15, 4, 2, 11, 6, 7, 12, 0, 5, 14, 9,
// S3
10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8,
13, 7, 0, 9, 3, 4, 6, 10, 2, 8, 5, 14, 12, 11, 15, 1,
13, 6, 4, 9, 8, 15, 3, 0, 11, 1, 2, 12, 5, 10, 14, 7,
1, 10, 13, 0, 6, 9, 8, 7, 4, 15, 14, 3, 11, 5, 2, 12,
// S4
7, 13, 14, 3, 0, 6, 9, 10, 1, 2, 8, 5, 11, 12, 4, 15,
13, 8, 11, 5, 6, 15, 0, 3, 4, 7, 2, 12, 1, 10, 14, 9,
10, 6, 9, 0, 12, 11, 7, 13, 15, 1, 3, 14, 5, 2, 8, 4,
3, 15, 0, 6, 10, 1, 13, 8, 9, 4, 5, 11, 12, 7, 2, 14,
// S5
2, 12, 4, 1, 7, 10, 11, 6, 8, 5, 3, 15, 13, 0, 14, 9,
14, 11, 2, 12, 4, 7, 13, 1, 5, 0, 15, 10, 3, 9, 8, 6,
4, 2, 1, 11, 10, 13, 7, 8, 15, 9, 12, 5, 6, 3, 0, 14,
11, 8, 12, 7, 1, 14, 2, 13, 6, 15, 0, 9, 10, 4, 5, 3,
// S6
12, 1, 10, 15, 9, 2, 6, 8, 0, 13, 3, 4, 14, 7, 5, 11,
10, 15, 4, 2, 7, 12, 9, 5, 6, 1, 13, 14, 0, 11, 3, 8,
9, 14, 15, 5, 2, 8, 12, 3, 7, 0, 4, 10, 1, 13, 11, 6,
4, 3, 2, 12, 9, 5, 15, 10, 11, 14, 1, 7, 6, 0, 8, 13,
// S7
4, 11, 2, 14, 15, 0, 8, 13, 3, 12, 9, 7, 5, 10, 6, 1,
13, 0, 11, 7, 4, 9, 1, 10, 14, 3, 5, 12, 2, 15, 8, 6,
1, 4, 11, 13, 12, 3, 7, 14, 10, 15, 6, 8, 0, 5, 9, 2,
6, 11, 13, 8, 1, 4, 10, 7, 9, 5, 0, 15, 14, 2, 3, 12,
// S8
13, 2, 8, 4, 6, 15, 11, 1, 10, 9, 3, 14, 5, 0, 12, 7,
1, 15, 13, 8, 10, 3, 7, 4, 12, 5, 6, 11, 0, 14, 9, 2,
7, 11, 4, 1, 9, 12, 14, 2, 0, 6, 10, 13, 15, 3, 5, 8,
2, 1, 14, 7, 4, 10, 8, 13, 15, 12, 9, 0, 3, 5, 6, 11
};
//bytetobit函数完成密码字节到bit的转换。encrypt中存放要转换的字节,table1中存放转换结果,n1为table1的表长,n2为转换字节的开始点。
bool bytetobit(char encrypt[9], char table1[64], int n1,int n2)
{
for (j=n2;j<n2+8;j++)
{
for (j1=8;j1>0;j1--)
{
switch (j1)
{
case 1: table1[(j-n2)*8+8-j1]=encrypt[j] & 1;
break;
case 2: table1[(j-n2)*8+8-j1]=encrypt[j] & 2;
break;
case 3: table1[(j-n2)*8+8-j1]=encrypt[j] & 4;
break;
case 4: table1[(j-n2)*8+8-j1]=encrypt[j] & 8;
break;
case 5: table1[(j-n2)*8+8-j1]=encrypt[j] & 0x10;
break;
case 6: table1[(j-n2)*8+8-j1]=encrypt[j] & 0x20;
break;
case 7: table1[(j-n2)*8+8-j1]=encrypt[j] & 0x40;
break;
case 8: table1[(j-n2)*8+8-j1]=encrypt[j] & 0x80;
break;
default:table1[(j-n2)*8+8-j1]=0 ;
break;
}
table1[(j-n2)*8+8-j1]=table1[(j-n2)*8+8-j1]&&table1[(j-n2)*8+8-j1];//位与位相与是一个&符,而逻辑与是两个&&符。意思是只要table1[j]为零不变,不为零就令table1[j]等于1。
}
}
return true;
};
//table_chang是表的转换:table1是要转换的表,table2是要转换表存放的顺序,table3是最终转换的结果,n1是转换后表的长度。
bool table_chang(char table1[64],char table2[64],char table3[64], short int n1)
{
for (j=0;j<n1;j++)
{
a=table2[j];
table3[j]=table1[a-1];
}
return true;
};
bool table_lr(char table1[64],char table3[64], short int n1,short int n2)//表的环移:table1是要环移的表,n1是table1的长度,table3是最终环移后的结果,n2是多少位。
{
for (j=0;j<n1;j++)
{
table3[j]=table1[(j+n2)%n1];
}
return true;
};
// initial permutation IP
char IP_Table_first[64] = {
58, 50, 42, 34, 26, 18, 10, 2, 60, 52, 44, 36, 28, 20, 12, 4,
62, 54, 46, 38, 30, 22, 14, 6, 64, 56, 48, 40, 32, 24, 16, 8,
57, 49, 41, 33, 25, 17, 9, 1, 59, 51, 43, 35, 27, 19, 11, 3,
61, 53, 45, 37, 29, 21, 13, 5, 63, 55, 47, 39, 31, 23, 15, 7
};
// final permutation IP^-1
char IP_Table_last[64] = {
40, 8, 48, 16, 56, 24, 64, 32, 39, 7, 47, 15, 55, 23, 63, 31,
38, 6, 46, 14, 54, 22, 62, 30, 37, 5, 45, 13, 53, 21, 61, 29,
36, 4, 44, 12, 52, 20, 60, 28, 35, 3, 43, 11, 51, 19, 59, 27,
34, 2, 42, 10, 50, 18, 58, 26, 33, 1, 41, 9, 49, 17, 57, 25
};
// expansion operation matrix
char E_Table[48] = {
32, 1, 2, 3, 4, 5, 4, 5, 6, 7, 8, 9,
8, 9, 10, 11, 12, 13, 12, 13, 14, 15, 16, 17,
16, 17, 18, 19, 20, 21, 20, 21, 22, 23, 24, 25,
24, 25, 26, 27, 28, 29, 28, 29, 30, 31, 32, 1
};
// 32-bit permutation function P used on the output of the S-boxes
char P_Table[32] = {
16, 7, 20, 21, 29, 12, 28, 17, 1, 15, 23, 26, 5, 18, 31, 10,
2, 8, 24, 14, 32, 27, 3, 9, 19, 13, 30, 6, 22, 11, 4, 25
};
//F函数主要实现table1的32_48扩展、与子密钥异或、用S盒实现48_32转换、32_32的置换,
//最后与table2异或。结果放入table2中,但table1中的值要一直保持不变。ki为密钥的序号。
void F_function(char table1[64],char table2[64],short int ki)
{
table_chang(table1,E_Table,table3,48);//32_48扩展
for (j=0;j<8;j++)//与子密钥异或、用S盒实现48_32转换
{
b5=subkey[ki+1][6*j+0]^table3[6*j+0];
b4=subkey[ki+1][6*j+1]^table3[6*j+1];
b3=subkey[ki+1][6*j+2]^table3[6*j+2];
b2=subkey[ki+1][6*j+3]^table3[6*j+3];
b1=subkey[ki+1][6*j+4]^table3[6*j+4];
b0=subkey[ki+1][6*j+5]^table3[6*j+5];
table3[4*j+0]=s_box_bit[j][b5][b0][b4][b3][b2][b1][0];
table3[4*j+1]=s_box_bit[j][b5][b0][b4][b3][b2][b1][1];
table3[4*j+2]=s_box_bit[j][b5][b0][b4][b3][b2][b1][2];
table3[4*j+3]=s_box_bit[j][b5][b0][b4][b3][b2][b1][3];
}
table_chang(table3,P_Table,table4,32);//32_32的置换
for (j=0;j<32;j++)
{
table2[j]=table2[j]^table4[j];
}
};
int main()
{ cout << "\n程序编制人:jmjpc\n";
cout << "\n二○○八年十一月二十九日编制。\n";
choice: cout << "\n请选择:1=加密文件, 2=脱密文件 ";
cin>>b;
// cin.ignore(1,'\n');//吃掉缓冲区中的回车符,否则下次无法输入。
switch (b)
{
case 1: cout <<"\nOK,准备加密文件。\n \n";
break;
case 2: cout <<"\nOK,准备脱密文件。\n \n";
break;
default:cout <<"对不起,选择错误,请重新选择。\n";
goto choice;
break;
}
while (b==1)
{
cout <<"请输入要加密的文件名:";
choice1: cin >> wenjian_read;
cin.ignore(1,'\n'); //吃掉缓冲区中的回车符,否则下次无法输入。
ifstream fin(wenjian_read,ios::nocreate|ios::binary); //文件不存在时,打开失败,若用ifstream fin(fileName)语句,文件不存在时,就直接创建。
if(!fin)
{ cout << "不能打开文件" << wenjian_read <<"\n";
cout <<"请重新输入要加密的文件名:";
goto choice1;
return (1);}
fin.close();
cout <<"\n加密后的文件存为:";
break;
}
while (b==2)
{
cou