flask-pymongo:PyMongo对Flask应用程序的支持

Flask-PyMongo PyMongo对Flask应用程序的支持 快速开始 from flask import Flask , render_template from flask_pymongo import PyMongo app = Flask ( __name__ ) app . config [ "MONGO_URI" ] = "mongodb://localhost:27017/myDatabase" mongo = PyMongo ( app ) @ app . route ( '/' ) def home_page (): online_users = mongo . db . users . find ({ 'online' : True }) return render_template ( 'index.html' , online_users