python json 递归打印所有json子节点信息的例子
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2020-12-20
11:38:27
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python json 递归打印所有递归打印所有json子节点信息的例子子节点信息的例子
我就废话不多说了，直接上代码吧
def json_txt(self, dic_json):
#self.debug_print("json_txt")
if isinstance(dic_json, dict): # 判断是否是字典类型isinstance 返回True false
for key in dic_json:
#dic_json = json.loads(s)
s = dic_json[key] #self.debug_print(str(len(s)) + " type:" + str(type(s)))
t=str(type(s))
if t.startswith("<class 'list'>"):
for i in range(0, len(s)):
self.debug_print("%s %d:" % (key, i))
self.json_txt(s[i])
else:
self.debug_print("%s: %s" % (key, s))
else:
self.debug_print("else")
补充拓展：补充拓展：python求求json某层节点的和实例某层节点的和实例
如下所示：如下所示：
import json
from collections import Mapping
import json
def dict_generator(indict, pre=None):
pre = pre[:] if pre else [] if isinstance(indict, dict):
for key, value in indict.items():
if isinstance(value, dict):
if len(value) == 0:
yield pre+[key, ‘{}'] else:
for d in dict_generator(value, pre + [key]):
yield d
elif isinstance(value, list):
if len(value) == 0:
yield pre+[key, ‘[]'] else:
for v in value:
for d in dict_generator(v, pre + [key]):
yield d
elif isinstance(value, tuple):
if len(value) == 0:
yield pre+[key, ‘()'] else:
for v in value:
for d in dict_generator(v, pre + [key]):
yield d
else:
yield pre + [key, value] else:
yield indict
def recursive_findall(obj, key, paths=None):
ret = [] if not paths:
paths = [] if isinstance(obj, Mapping):
for k, v in obj.iteritems():
found_items = recursive_findall(v, key, paths=(paths + [(‘k', k)]))
ret += found_items
elif isinstance(obj, (list, tuple)):
for i, v in enumerate(obj):
found_items = recursive_findall(v, key, paths=(paths + [(‘i', i)]))
ret += found_items
else:
if key(obj):
ret.append((paths, obj))
return ret
ret_dict = {
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