C语言实现直角坐标转换为极坐标的方法语言实现直角坐标转换为极坐标的方法
主要介绍了C语言实现直角坐标转换为极坐标的方法,涉及C语言进行三角函数与数值运算相关操作技巧,需要的
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本文实例讲述了C语言实现直角坐标转换为极坐标的方法。分享给大家供大家参考，具体如下：
#include<stdio.h>
#include<math.h>
struct complex_s{
double x,y;
};
double real_part(struct complex_s z){
return z.x;
}
double img_part(struct complex_s z){
return z.y;
}
double magnitude(struct complex_s z){
return sqrt(z.x*z.x + z.y*z.y);
}
double angle(struct complex_s z){
return atan2(z.y, z.x);
}
struct complex_s make_from_real_img(double x, double y){
struct complex_s z;
z.x = x;
z.y = y;
return z;
}
struct complex_s make_from_mag_ang(double r, double A){
struct complex_s z;
z.x = r * cos(A);
z.y = r * sin(A);
return z;
}
struct complex_s add_complex(struct complex_s z1,struct complex_s z2){
return make_from_real_img(real_part(z1)+real_part(z2),
img_part(z1) + img_part(z2));
}
struct complex_s sub_complex(struct complex_s z1,struct complex_s z2){
return make_from_real_img(real_part(z1)-real_part(z2),
img_part(z1) - img_part(z2));
}
struct complex_s mul_complex(struct complex_s z1,struct complex_s z2){
return make_from_mag_ang(real_part(z1)*real_part(z2),
img_part(z1) + img_part(z2));
}
struct complex_s div_complex(struct complex_s z1,struct complex_s z2){
return make_from_mag_ang(real_part(z1)/real_part(z2),
img_part(z1) + img_part(z2));
}
int main(void){
struct complex_s z1 = {3.0,4.0};
struct complex_s z2= {2.0,5.0};
struct complex_s x;
x = add_complex(z1,z2);
printf("x={%f,%f}",x.x,x.y);
return 0;
}
结果：
[root@localhost struct]# ./jizuobiao.out
x={5.000000,9.000000}
希望本文所述对大家C语言程序设计有所帮助。
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