没有合适的资源?快使用搜索试试~ 我知道了~
∧-1-ford稳定环上二次型群的K1,游宏,叶圣奎,在Bass ∧-1-ford稳定条件下给出二次型群的KU1的刻画
资源推荐
资源详情
资源评论
Prestability for Quadratic K
1
of Λ-1-Fold
Stable Rings
Hong You
1
1) Department of Mathematics, Suzhou University, Suzhou 215006, P. R. China
2) Department of Mathematics, Harbin Institute of Technology, Harbin 150001, P. R. China
Shengkui Ye
Department of Mathematics, Harbin Institute of Technology, Harbin 150001, P. R. China
Abstract
The general quadratic group U
2n
and its elementary subgroup EU
2n
are analogs in the
theory of the general linear group GL
n
and its elementary subgroup E
n
. It is known, for
GL
n
, K
1
= GL
1
/ < (a + c + abc)(a + c + cba)
−1
| a + c + abc ∈ GL
1
> under the first Bass
stable range condition on the ring of entries. In this article we give a description for KU
1
under the Λ-1-fold stable range condition on the ring of entries.
Mathematics Subject Classification (2000) : 19B99, 19C99, 19G38
Key Words : prestability, quadratic forms, Λ-1-fold condition
1. Introduction
Let R be an associative ring with 1 and assume that an anti-automorphism − : x 7→ x
is defined on R such that
x = εxε for some unit ε = ε
−1
of R and every x in R. It
also determines an anti-automorphism of the ring M
n
R of all n by n matrices (x
ij
) by
(x
ij
) = (x
ji
).
Set R
ε
= {x − xε| x ∈ R}, R
ε
= {x ∈ R | x = −xε} . We fix an additive subgroup Λ of
R with the following properties:
(i) rΛr ⊂ Λ for all r ∈ R;
(ii) R
ε
⊂ Λ ⊂ R
ε
.
In the present paper we assume R
ε
6= 0.
Let
Λ
n
= {(a
ij
) ∈ M
n
R | a
ij
= −a
ji
ε for i 6= j and a
ii
∈ Λ}.
1
Supported by NSF of China and RFDP of Ministry of Education
E-mail address: 1) youhong@suda.edu.cn 2) hyou@hit.edu.cn
1
http://www.paper.edu.cn
As in [3, 4], we define
U
2n
(R, Λ) =
½µ
α β
γ δ
¶
∈ GL
2n
R | αδ + γεβ = I
n
, αγ, βδ ∈ Λ
n
¾
as the general quadratic group of rank n.
By [4, Lemma 2.1], an invertible 2n×2n matrix σ =
µ
α β
γ δ
¶
is an element of U
2n
(R, Λ)
if and only if the following conditions hold:
(i) σϕ
n
σ = ϕ
n
where ϕ
n
=
µ
0 I
εI 0
¶
,
(ii) the diagonal entries of
αγ, βδ lie in Λ.
Moreover condition (i) is equivalent to the following condition
(i)
0
µ
α β
γ δ
¶
−1
=
µ
εδε εβ
γε α
¶
. (1.1)
There is an obvious embedding
U
2n
(R, Λ) → U
2(n+1)
(R, Λ),
µ
α β
γ δ
¶
→
α 0 β 0
0 1 0 0
γ 0 δ 0
0 0 0 1
, (1.2)
and using this map, we shall frequently want to consider U
2n
(R, Λ) as a subgroup of
U
2(n+1)
(R, Λ).
With n fixed for any 1 ≤ k ≤ 2n, set σk = k + n if k ≤ n and σk = k − n if k > n. For
a ∈ R and 1 ≤ i 6= j ≤ 2n we define the elementary quadratic matrices ρ
i,σi
(a) and ρ
i,j
(a)
with j 6= σi as follows: ρ
i,σi
(a) = I
2n
+ aE
i,σi
with a ∈ Λ when n + 1 ≤ i and
a ∈ Λ when
i ≤ n. ρ
ij
(a) = ρ
σj,σi
(−a
0
) = I
2n
+ aE
ij
− a
0
E
σj,σi
∈ U
2n
(R, Λ) with a
0
=
a when i, j ≤ n;
a
0
=
ε a when i ≤ n < j; a
0
= aε when j ≤ n < i; and a
0
= ε aε when n + 1 ≤ i, j.
The subgroup of U
2n
(R, Λ) generated by these matrices is denoted by EU
2n
(R, Λ). The
stabilization map U
2n
(R, Λ) → U
2(n+1)
(R, Λ) above induces a stabilization map EU
2n
(R, Λ) →
EU
2(n+1)
(R, Λ) which will be used frequently to identify EU
2n
(R, Λ) with its image in
EU
2(n+1)
(R, Λ).
Define
U(R, Λ) = lim
−→
U
2n
(R, Λ), EU(R, Λ) = lim
−→
EU
2n
(R, Λ),
2
http://www.paper.edu.cn
剩余11页未读,继续阅读
资源评论
weixin_38502915
- 粉丝: 5
- 资源: 914
上传资源 快速赚钱
- 我的内容管理 展开
- 我的资源 快来上传第一个资源
- 我的收益 登录查看自己的收益
- 我的积分 登录查看自己的积分
- 我的C币 登录后查看C币余额
- 我的收藏
- 我的下载
- 下载帮助
最新资源
资源上传下载、课程学习等过程中有任何疑问或建议,欢迎提出宝贵意见哦~我们会及时处理!
点击此处反馈
安全验证
文档复制为VIP权益,开通VIP直接复制
信息提交成功