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2016302580242-刘瑞康-作业41
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2022-08-08
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2016302580242-刘瑞康-作业41
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3.5
将训练样本进行规范化处理
X
1
=[0,0,0,1]
T
,
X
2
=[1,0,0,1]
T
,
X
3
=[1,0,1,1]
T
,
X
4
=[1,1,0,1]
T
X
5
=[0,0,-1,-1]
T
,
X
6
=[0,-1,-1,-1]
T
,
X
7
=[0,-1,0,-1]
T
,
X
8
=[-1,-1,-1,-1]
T
取 W(1) = (0, 0, 0, 0)
T
,c = 1。迭代过程如下。
第一轮:
W
T
(1)X
1
= [-1,-2,-2,0][0,0,0,1]
T
= 0, W(2) = W(1) + X
1
= [-1,-2,-2,1]
T
W
T
(2)X
2
= [-1,-2,-2,1][1,0,0,1]
T
= 0, W(3) = W(2) + X
2
= [0,-2,-2,2]
T
W
T
(3)X
3
= [0,-2,-2,2][1,0,1,1]
T
= 0, W(4) = W(3) + X
3
= [1,-2,-1,3]
T
W
T
(4)X
4
= [1,-2,-1,3][1,1,0,1]
T
= 2 > 0, W(5) = W(4)
W
T
(5)X
5
= [1,-2,-1,3][0,0,-1,-1]
T
= -2 < 0, W(6) = W(5) + X
5
= [1,-2,-2,2]
T
W
T
(6)X
6
= [1,-2,-2,2][0,-1,-1,-1]
T
= 2 > 0, W(7) = W(6)
W
T
(7)X
7
= [1,-2,-2,2][0,-1,0,-1]
T
= 0, W(8) = W(7) + X
7
= [1,-3,-2,1]
T
W
T
(8)X
8
= [1,-3,-2,1][-1,-1,-1,-1]
T
= 3 > 0, W(9) = W(8)
第二轮:
W
T
(9)X
1
= [1,-3,-2,1][0,0,0,1]
T
= 1 > 0, W(10) = W(9)
W
T
(10)X
2
= [1,-3,-2,1][1,0,0,1]
T
= 2 > 0, W(11) = W(9)
W
T
(11)X
3
= [1,-3,-2,1][1,0,1,1]
T
= 0, W(12) = W(11) + X
3
= [2,-3,-1,2]
T
W
T
(12)X
4
= [2,-3,-1,2][1,1,0,1]
T
= 1 > 0, W(13) = W(12)
W
T
(13)X
5
= [2,-3,-1,2][0,0,-1,-1]
T
= -1 < 0, W(14) = W(13) + X
5
= [2,-3,-2,1]
T
W
T
(14)X
6
= [2,-3,-2,1][0,-1,-1,-1]
T
= 4 > 0, W(15) = W(14)
W
T
(15)X
7
= [2,-3,-2,1][0,-1,0,-1]
T
= 2 > 0, W(16) = W(15)
W
T
(16)X
8
= [2,-3,-2,1][-1,-1,-1,-1]
T
= 2 > 0, W(17) = W(16)
第三轮:
W
T
(17)X
1
= [2,-3,-2,1][0,0,0,1]
T
= 1 > 0, W(18) = W(17)
W
T
(18)X
2
= [2,-3,-2,1][1,0,0,1]
T
= 3 > 0, W(19) = W(18)
W
T
(19)X
3
= [2,-3,-2,1][1,0,1,1]
T
= 1 > 0, W(20) = W(19)
W
T
(20)X
4
= [2,-3,-2,1][1,1,0,1]
T
= 0, W(21) = W(20) + X
4
= [3,-2,-2,2]
T
W
T
(21)X
5
= [3,-2,-2,2][0,0,-1,-1]
T
= 0, W(22) = W(21) + X
5
= [3,-2,-3,1]
T
W
T
(22)X
6
= [3,-2,-3,1][0,-1,-1,-1]
T
= 4 > 0, W(23) = W(22)
W
T
(23)X
7
= [3,-2,-3,1][0,-1,0,-1]
T
= 1 > 0, W(24) = W(23)
W
T
(24)X
8
= [3,-2,-3,1][-1,-1,-1,-1]
T
= 1 > 0, W(25) = W(24)
第四轮:
W
T
(25)X
1
= [3,-2,-3,1[0,0,0,1]
T
= 1 > 0, W(26) = W(25)
W
T
(26)X
2
= [3,-2,-3,1][1,0,0,1]
T
= 4 > 0, W(27) = W(26)
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