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= 10(2 − 1)(3 − 1)(4 − 1)(3 − 2)(4 − 2)(4 − 3)= (−3) × (−2)(2 + 1) = 18.= (λ − 1
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z
E
1.
} b 1 2 = m
D =
1 2 1
2 3 a + 2
1 a −2
r
2
+ r
1
× (−2)
r
3
− r
1
1 2 1
0 −1 a
0 a −2 −3
= 3 −a(a − 2) = −a
2
+ 2a + 3 = −(a − 3)(a + 1)6= 0.
e
, a 6= 3
a 6= −1.
^ $
A =
1 2 1
2 3 a + 2
1 a −2
r
2
+r
1
×(−2)
−−−−−−→
r
3
−r
1
1 2 1
0 −1 a
0 a − 2 −3
r
3
+r
2
×(a−2)
−−−−−−−→
1 2 1
0 −1 a
0 0 −3 + a
2
− 2a
,
g ? u p h : +
r(A) = 3.
j J
a
2
− 2a − 3 = (a − 3)(a + 1)6= 0.
O
,a 6= 3
a 6= −1.
2.
}
(
^ $
)
˜
A =
1 2 1 1
2 3 a + 2 3
1 a −2 0
r
2
+r
1
×(−2)
−−−−−−→
r
3
−r
1
1 2 1 1
0 −1 a 1
0 a − 2 −3 −1
r
3
+r
2
×(a−2)
−−−−−−−→
1 2 1 1
0 −1 a 1
0 0 a
2
− 2a − 3 a − 3
,
r(A) 6= r(
˜
A)
F
,
? u W +
.
a
2
− 2a − 3 = (a − 3)(a + 1) 6= 0
F
,r(A) = r(
˜
A) = 3,
u h T b +
;
a = 3
F
,r(A) = r(
˜
A) = 2 < 3,
u h W A +
;
a = −1
F
,
˜
A →
1 2 1 1
0 −1 −1 1
0 0 0 −4
,
r(A) = 2 6= r(
˜
A) = 3,
u W +
.
O
,
Æ U
a = −1.
3.
}
(
^ $
)
? u h 7 S + \ 8
,
k # s uh W A +
.
˜
A=
1 −1 −a 3
2 0 −3 1
−2 a 10 4
r
3
+r
2
−−−−−−−→
r
2
+r
1
×(−2)
1 −1 −a 3
0 2 −3 + 2a −5
0 a 7 5
1
r
3
+r
2
×(−
a
2
)
−−−−−−−→
1 −1 −a 3
0 2 −3 + 2a −5
0 0 −a
2
+
3
2
a + 7
5
2
a + 5
→
1 −1 −a 3
0 2 −3 + 2a −5
0 0 −
1
2
(2a − 7)(a + 2)
5
2
(a + 2)
,
a = −2
F
, r(A) = r(
˜
A) = 2 < 3,
u h W A +
.
L
1.
} u Y K - o w ^ $
,
A =
3 −5 5 −3
1 −2 3 −1
2 −3 2 −2
→
1 −2 3 −1
0 1 −4 0
0 0 0 0
→
1 0 −5 −1
0 1 −4 0
0 0 0 0
.
g
r(A) = 2 < 4,
u h : +
.
S + u U
x
1
= 5x
3
+ x
4
x
2
= 4x
3
.
u R + U
x
1
x
2
x
3
x
4
= k
1
5
4
1
0
+ k
2
1
0
0
1
, k
1
, k
2
U D d K
.
2.
} u n " - o w ^ $
,
˜
A =
3 −5 5 −3 2
1 −2 3 −1 1
2 −3 2 −2 1
→
1 −2 3 −1 1
0 1 −4 0 −1
0 0 0 0 0
g j
r(
˜
A) = r(A) = 2 < 4,
O u h W A +
.
g
˜
A →
1 0 −5 −1 −1
0 1 −4 0 −1
0 0 0 0 0
S + u U
x
1
= −1 + 5x
3
+ x
4
x
2
= −1 + 4x
3
.
u R + U
x
1
x
2
x
3
x
4
=
−1
−1
0
0
+ k
1
5
4
1
0
+ k
2
1
0
0
1
, k
1
, k
2
U D d K
.
2
3.
} f6 5 B ! + V Q
.
x
1
+ x
2
+ x
3
= 0
x
1
+ 2x
2
+ ax
3
= 0
x
1
+ 4x
2
+ a
2
x
3
= 0
x
1
+ 2x
2
+ x
3
= a − 1
˜
A =
1 1 1 0
1 2 a 0
1 4 a
2
0
1 2 1 a − 1
r
2
− r
1
r
3
− r
1
−−−−−→
r
4
− r
1
1 1 1 0
0 1 a − 1 0
0 3 a
2
− 1 0
0 1 0 a − 1
→
1 1 1 0
0 1 0 a − 1
0 0 a − 1 −a + 1
0 0 a
2
− 1 −3(a − 1)
→
1 1 1 0
0 1 0 a − 1
0 0 a − 1 −a + 1
0 0 0 (a −1)(a − 2)
a G u h +
,
` h
(a − 1)(a − 2) = 0,
a = 1
%
a = 2.
a = 1
F
,
˜
A →
1 1 1 0
0 1 0 0
0 0 0 0
0 0 0 0
,
! + U
X = k
−1
0
1
, ∀k ∈ P.
a = 2
F
,
˜
A →
1 0 1 −1
0 1 0 1
0 0 1 −1
0 0 0 0
→
1 0 0 0
0 1 0 1
0 0 1 −1
0 0 0 0
! + U
X =
0
1
−1
.
3
z {
E
1.
}
|B| = 2
a
11
a
13
a
11
+ a
12
a
21
a
23
a
21
+ a
22
a
31
a
33
a
31
+ a
32
c
3
− c
1
2
a
11
a
13
a
12
a
21
a
23
a
22
a
31
a
33
a
32
c
3
↔ c
2
−2
a
11
a
12
a
13
a
21
a
22
a
23
a
31
a
32
a
33
= −2m.
2.
}
D
r
1
+ r
4
10 10 10 10
1 2
2
3
2
4
2
1 2
3
3
3
4
3
1 2 3 4
= 10
1 1 1 1
1 2
2
3
2
4
2
1 2
3
3
3
4
3
1 2 3 4
r
4
↔ r
3
r
3
↔ r
2
10
1 1 1 1
1 2 3 4
1 2
2
3
2
4
2
1 2
3
3
3
4
3
= 10V (1, 2, 3, 4)
= 10(2 − 1)(3 − 1)(4 − 1)(3 − 2)(4 − 2)(4 − 3)
= 120
3.
}
|A|
c
n
+ c
1
+ ··· + c
n−1
a
11
a
12
··· b
a
21
a
22
··· b
.
.
.
.
.
.
.
.
.
a
n1
a
n2
··· b
= b
a
11
a
12
··· 1
a
21
a
22
··· 1
.
.
.
.
.
.
.
.
.
a
n1
a
n2
··· 1
= b(A
1n
+ A
2n
+ ···+ A
nn
)= a
A
1n
+ A
2n
+ ···+ A
nn
=
a
b
.
4.
}
A
11
+ 2A
21
+ A
31
+ 2A
41
=
1 2 3 4
2 3 4 6
1 4 1 2
2 2 2 2
= 2
1 2 3 4
2 3 4 6
1 4 1 2
1 1 1 1
c
2
− c
1
c
3
− c
1
c
4
− c
1
2
1 1 2 3
2 1 2 4
1 3 0 1
1 0 0 0
= −2
1 2 3
1 2 4
3 0 1
r
2
− r
1
r
3
+ r
1
× (−3)
−2
1 2 3
0 0 1
0 −6 −8
= −12
5.
}
f(x)
K [ U
f(0) =
0 5 1 1
2 0 −1 2
−2 4 0 0
0 −3 0 0
= −3
0 1 1
2 −1 2
−2 0 0
= (−3) × (−2)(2 + 1) = 18.
1
6.
}
[
b
]
x = a
1
F v
=
a
1
a
1
a
2
a
3
a
1
a
1
a
2
a
3
a
1
a
2
a
1
a
3
a
1
a
2
a
3
a
1
= 0,
h
x
1
= a
1
.
S 4
,
h
x
2
= a
2
, x
3
= a
3
.
i ^ 9 I 9 / H ; b 9 ( b 9 l P C b 9 e t
x + a
1
+ a
2
+ a
3
,
x
4
= −(a
1
+ a
2
+ a
3
).
O h
x
1
= a
1
, x
2
= a
2
, x
3
= a
3
, x
4
= −(a
1
+ a
2
+ a
3
).
[
]
9 / H ; b 9 ( b 9
v
=
x + a
1
+ a
2
+ a
3
a
1
a
2
a
3
x + a
1
+ a
2
+ a
3
x a
2
a
3
x + a
1
+ a
2
+ a
3
a
2
x a
3
x + a
1
+ a
2
+ a
3
a
2
a
3
x
r
4
− r
3
r
3
− r
2
r
2
− r
1
x + a
1
+ a
2
+ a
3
a
1
a
2
a
3
0 x − a
1
0 0
0 a
2
− x x −a
2
0
0 0 a
3
− x x −a
3
= (x + a
1
+ a
2
+ a
3
) (x − a
1
)(x − a
2
)(x − a
3
) = 0.
O h
x
1
= a
1
, x
2
= a
2
, x
3
= a
3
, x
4
= −(a
1
+ a
2
+ a
3
).
X
1.
}
D =
λ − 3 −2 2
k λ + 1 −k
−4 −2 λ + 3
c
1
+ c
3
λ − 1 −2 2
0 λ + 1 −k
λ − 1 −2 λ + 3
r
3
− r
1
λ − 1 −2 2
0 λ + 1 −k
0 0 λ + 1
= (λ − 1)(λ + 1)
2
= 0,
λ = 1, λ = −1 (
r
).
2.
}
D =
5 3 −1 2 0
1 7 2 5 2
0 −2 3 1 0
0 −4 −1 4 0
0 2 3 5 0
= 2 × (−1)
5 3 −1 2
0 −2 3 1
0 −4 −1 4
0 2 3 5
= −2 × 5
−2 3 1
−4 −1 4
2 3 5
r
2
+ r
1
(−2)
r
3
+ r
1
− 10
−2 3 1
0 −7 2
0 6 6
= −10 × (−2)(−42 − 12) = −1080.
2
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