2018300001031-吴远清-电动力学第十章作业1
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电动力学-第十章作业
吴远清-2018300001031
2020 年 6 月 19 日
Problem 12.16
Answer:
(a)
Let the time in the frame of the stationary twin on Earth be
¯
t, then:
∆
¯
t = γ
t
R
+
x
R
v
c
2
− γ
t
S
+
x
S
v
c
2
= γ∆t =
5
3
· 18 = 30y
where x
R
= x
S
= 0 since the two origins coincide at start and return.
Subscript ”R” stands for ”return” and ”S” for ”start”. Her twin is thus 51
years old.
(b)
In which system? In the Earth system the star is 15 years of travel away,
so it’s:
L = 15 ·
4
5
c = [12y
(c)
since the jump happens at the star X, the coordinates of the jump is the
Earth system are obviously (t, x) = (15y, 12cy)
Let the Earth system be S, inbound one
˜
S and outbound one S, with
t =
¯
t =
˜
t = 0 at x = ¯x = ˜x = 0
(d)
This system travels with her (on the outbound trip), so the jump happens
at (
¯
t, ¯x) = (9y, 0)
(e)
1
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