【基础算法】-python鸡兔同笼
# 方法一
def solve_chicken_rabbit(n, m):
for x in range(n+1):
y = n - x
if 2*x + 4*y == m:
return x, y
return None
# 测试代码
n = 10
m = 32
result = solve_chicken_rabbit(n, m)
if result:
x, y = result
print(f"鸡的数量为{x}，兔的数量为{y}")
else:
print("无解")
# 方法二
total_count = int(input("请输入总数量: "))
total_legs = int(input("请输入总腿数: "))
