Day6-指针专项一案例代码

#include <stdio.h> int main(int argc,char *argv[]) { int a = 10; int *p1; int *p2; char b[] = "xiaoqiang"; char *p3; p1 = &a; p2 = p1; printf("a =%d *p1=%d *p2=%d\n",a,*p1,*p2); printf("&a=%p p1=%p p2=%p\n",&a,p1,p2); printf("&p1=%p &p2=%p\n",&p1,&p2); puts("---------p3=b-----------"); p3 = b; printf("b=%s,*p3=%c,p3=%s\n",b,*p3,p3); printf("&b=%p,p3=%p,&p3=%p\n",&b,p3,&p3); return 0; }