§3 复化求积 /* Composite Quadrature */
Haven’t we had enough
formulae? What’s up
now?
Oh come on,
you don’t seriously consider
h=(b�a)/2 acceptable,
do you?
Why can’t you simply
refine the partition if you have to
be so picky?
Don’t you forget
the oscillatory nature of high-
degree polynomials!
Uh-oh
高次插值有Runge 现象,故采用分段低次插值
� 分段低次合成的 Newton-Cotes 复化求积公式。
复化梯形公式:
在每个 上用梯形公式:
= T
n
/*中值定理*/