LR(1)分析法实验

部分代码如下：需要的可联系我：QQ627845967 #include"iostream.h" #include "stdio.h" #include "malloc.h" #include "conio.h" struct Lchar{ char char_ch; struct Lchar *next; }Lchar,*p,*h,*temp,*top,*base; char curchar; char curtocmp; int right; int table[5][8]={{1,0,0,1,0,0}, {0,1,0,0,1,1}, {1,0,0,1,0,0}, {0,1,1,0,1,1}, {1,0,0,1,0,0}}; int i,j; void push(char pchar) { temp=(struct Lchar*)malloc(sizeof(Lchar)); temp->char_ch=pchar; temp->next=top; top=temp; } void pop(void) { curtocmp=top->char_ch; if(top->char_ch!='#') top=top->next; } void doforpush(int t) { switch(t) { case 0:push('A');push('T');break; case 5:push('A');push('T');break; case 11:push('A');push('T');push('+');break; case 20:push('B');push('F');break; case 23:push('B');push('F');break; case 32:push('B');push('F');push('*');break; case 40:push('i');break; case 43:push(')');push('E');push('('); } } void changchartoint() { switch(curtocmp) { case 'A':i=1;break; case 'B':i=3;break; case 'E':i=0;break; case 'T':i=2;break; case 'F':i=4; } switch(curchar) { case 'i':j=0;break; case '+':j=1;break; case '*':j=2;break; case '(':j=3;break; case ')':j=4;break; case '#':j=5; } }