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数据结构与算法Java描述习题答案

数据结构

习题答案

Java描述

算法分析

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数据结构与算法Java描述习题答案 Data Structures and Algorithm Analysis in Java 3rd Edition Practice Answers 原作者答案

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Data Structures

and

Problem Solving

Using Java

™

(Third Edition)

Resouce Manual

Mark Allen Weiss

3rd ed IRM revised by Tim Herman

C H A P T E R

Primitive Java

1.2 Solutions To Exercises

In Short

1.1 Java source files end in

. j a v a

. Compiled files (containing j-code or byte-codes) end in

. c l a s s

1.2

/ /

, which extends to the end of the line and

/ *

and

/ * *

, both of which extend to a

* /

. Comments do

not nest.

1.3

b o o l e a n

b y t e

s h o r t

c h a r

i n t

l o n g

f l o a t

, and

d o u b l e

1.4

multiplies two primitive values, returning the result and not changing its two arguments.

* =

changes

the left-hand argument to the product of the left-hand argument and the right-hand argument. The

right-hand argument is unchanged.

1.5 Both the prefix and postfix increment operators add one to the target variable. The prefix operator uses

the new value of the variable in a larger expression; the postfix operator uses the prior value.

1.6 The

w h i l e

loop is the most general loop and performs a test at the top of the loop. The body is exe-

cuted zero or more times. The

d o

loop is similar, but the test is performed at the bottom of the loop;

thus the body is executed at least once. The

f o r

loop is used primarily for counting-like iteration and

consists of an initialization, test, and update along with the body.

1.7

b r e a k

is used to exit a loop. A labelled

b r e a k

exits the loop that is marked with a label.

b r e a k

is also

used to exit a

s w i t c h

statement, rather than stepping through to the next case.

1.8 The

c o n t i n u e

statement is used to advance to the next iteration of the loop.

1.9 Method overloading allows the reuse of a method name in the same scope as long as the signatures

(parameter list types) of the methods differ.

1.10 In call-by-value, the actual arguments are copied into the method’s formal parameters. Thus, changes

to the values of the formal parameters do not affect the values of the actual arguments.

In Theory

1.11 After line 1,

is 6,

is 9, and

is 13. After line 2,

is 7,

is 10, and

is 16. After line 3,

is 8,

11, and

is 18. After line 4,

is 9,

is 12, and

is 21.

1.12 The result is

t r u e

. Note that the precedence rules imply that the expression is evaluated as

(true&&false) || true

1.13 The behavior is different if

s t a t e m e n t s

contains a

c o n t i n u e

statement.

1.14 Because of call-by-value,

must be 0 after the call to method

. Thus the only possible output is

In Practice

1.15 An equivalent statement is:

while( true )

s t a t e m e n t

1.16 This question is harder than it looks because I/O facilities are limited, making it difficult to align

columns.

public class MultiplicationTable

{

public static void main( String [ ] args )

{

for( int i = 1; i < 10; i++ )

{

for( int j = 1; j < 10; j++ )

{

if( i * j < 10 )

System.out.print( “ “ );

System.out.print( i * j + “ “ );

}

System.out.println( );

}

1.17 The methods are shown below (without a supporting class); we assume that this is placed in a class

that already provides the

m a x

method for two parameters.

public static int max( int a, int b, int c )

{

return max( max( a, b ), c );

}

public static int max( int a, int b, int c, int d )

{

return max( max( a, b ), max( c, d ) );

}

1.18 The method is below:

public static boolean isLeap( int year )

{

return year % 4 == 0 &&

( year % 100 != 0 || year % 400 == 0 );

}

C H A P T E R

References

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