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国密k倍点测试中间数据
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2013-06-06
10:57:51
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计算K倍点的中间测试数据,国密SM2算法 分别列出了K=1,2,3,4,5,6,7,8,0xFFFF,0xFF00FFFF 所对应的倍点值 基点及模P为官方文档中的数据
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0x421DEBD6 1B62EAB6 746434EB C3CC315E 32220B3B ADD50BDC 4C4E6C14 7FEDD43D // Gx
0x0680512B CBB42C07 D47349D2 153B70C4 E5D7FDFC BFA36EA1 A85841B9 E46E09A2 // Gy
0x8542D69E 4C044F18 E8B92435 BF6FF7DE 45728391 5C45517D 722EDB8B 08F1DFC3 // p
0x787968B4 FA32C3FD 2417842E 73BBFEFF 2F3C848B 6831D7E0 EC65228B 3937E498 // a
k = 0x0000000000000000000000000000000000000000000000000000000000000001
Qx = 0x421DEBD61B62EAB6746434EBC3CC315E32220B3BADD50BDC4C4E6C147FEDD43D
Qy = 0x0680512BCBB42C07D47349D2153B70C4E5D7FDFCBFA36EA1A85841B9E46E09A2
k = 0x0000000000000000000000000000000000000000000000000000000000000002
Qx = 0x5E1E24ACC7FB884895BB954DE21FE26456357D9EE8A32410635F35CDFB0D2846
Qy = 0x8314D639881A8BAF1BDD076BF82B090020D80F7A5ACC3C56BDB61BBD305708F4
k = 0x0000000000000000000000000000000000000000000000000000000000000003
Qx = 0x126FE19E98F4548A976C436D97B8C8A8F14405FF9A6D58B556355D70C2C19E69
Qy = 0x4BD3A18E69CC107212729F6473030132DE0B75BF7482CA5510B532EF7BDDCB93
k = 0x0000000000000000000000000000000000000000000000000000000000000004
Qx = 0x7579488E................................................45FE9DFD
Qy = 0x53233A1C................................................E06D6ED4
k = 0x0000000000000000000000000000000000000000000000000000000000000005
Qx = 0x69FB7B95................................................BFB03FDB
Qy = 0x4B38C759................................................191BAB3B
k = 0x0000000000000000000000000000000000000000000000000000000000000006
Qx = 0x832CD887................................................F5BF7A50
Qy = 0x19785C14................................................1808C891
k = 0x0000000000000000000000000000000000000000000000000000000000000007
0x0680512B CBB42C07 D47349D2 153B70C4 E5D7FDFC BFA36EA1 A85841B9 E46E09A2 // Gy
0x8542D69E 4C044F18 E8B92435 BF6FF7DE 45728391 5C45517D 722EDB8B 08F1DFC3 // p
0x787968B4 FA32C3FD 2417842E 73BBFEFF 2F3C848B 6831D7E0 EC65228B 3937E498 // a
k = 0x0000000000000000000000000000000000000000000000000000000000000001
Qx = 0x421DEBD61B62EAB6746434EBC3CC315E32220B3BADD50BDC4C4E6C147FEDD43D
Qy = 0x0680512BCBB42C07D47349D2153B70C4E5D7FDFCBFA36EA1A85841B9E46E09A2
k = 0x0000000000000000000000000000000000000000000000000000000000000002
Qx = 0x5E1E24ACC7FB884895BB954DE21FE26456357D9EE8A32410635F35CDFB0D2846
Qy = 0x8314D639881A8BAF1BDD076BF82B090020D80F7A5ACC3C56BDB61BBD305708F4
k = 0x0000000000000000000000000000000000000000000000000000000000000003
Qx = 0x126FE19E98F4548A976C436D97B8C8A8F14405FF9A6D58B556355D70C2C19E69
Qy = 0x4BD3A18E69CC107212729F6473030132DE0B75BF7482CA5510B532EF7BDDCB93
k = 0x0000000000000000000000000000000000000000000000000000000000000004
Qx = 0x7579488E................................................45FE9DFD
Qy = 0x53233A1C................................................E06D6ED4
k = 0x0000000000000000000000000000000000000000000000000000000000000005
Qx = 0x69FB7B95................................................BFB03FDB
Qy = 0x4B38C759................................................191BAB3B
k = 0x0000000000000000000000000000000000000000000000000000000000000006
Qx = 0x832CD887................................................F5BF7A50
Qy = 0x19785C14................................................1808C891
k = 0x0000000000000000000000000000000000000000000000000000000000000007
资源评论
- yinggegege2015-09-29非常好,非常有帮助,用这个数据,测试了我们自己写的SM2算法。
- 冬泉谷的夏天2015-11-03这个数据很有帮助,能够帮助调试,便于测试中间数据。
- baidu_308766872016-05-30k=3时自己的程序与测试数据的x值差了一位,y值相等,用大数计算器算出的结果与我自己的结果一致,不确定是测试数据存在问题还是我的算法有误。
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