def euclidAlgo(larger, smaller):
if(smaller > larger):
temp = larger
larger = smaller
smaller = temp
rem = larger % smaller
if(rem == 0):
return smaller
return euclidAlgo(smaller, rem)
def extEuclidAlgo(a, b):
a, b = abs(a), abs(b)
x0, x1, y0, y1 = 1, 0, 0, 1
while b != 0:
q, a, b = a // b, b, a % b
x0, x1 = x1, x0 - q * x1
y0, y1 = y1, y0 - q * y1
return a, x0, y0
def generatePublic(p,q):
n = p*q
phi = (p-1)*(q-1)
e = 2
while(euclidAlgo(e,phi) != 1):
e = e+1
if(e >= phi):
return( "not possible since e < phi(n), phi(n)={0} and e = {1}" .format(phi,e))
return e
def generatePrivate(e,n):
phi = eulerPhi(n)
gcd = euclidAlgo(e,phi)
if(gcd == 1):
d = extEuclidAlgo(e,phi)[1]
else:
return ("not possible since the gcd of {0} and {1} is {2} and not 1" .format(e,phi,gcd))
return d
def primeFactors(number):
factors = []
for i in range(2, number + 1):
if(number % i == 0):
prime = True
for j in range(2, (i//2 + 1)):
if(i % j == 0):
prime = False
break
if (prime):
factors.append(i)
return factors
def eulerPhi(n):
factors = primeFactors(n)
phi = n
for i in range (0, len(factors)):
temp = 1 - (1/factors[i])
phi *= temp
return int(phi)
def encryptRSA(x,e,n):
return pow(x,e,n)
def decryptRSA(y,d,n):
return pow(y,d,n)
def paarExample():
print("Paar Example, p=3, q=11")
p = 3
q = 11
e = generatePublic(p,q)
d = generatePrivate(e,p*q)
print("phi: {0}" .format(eulerPhi(p*q)))
print("encryption key: {0}" .format(e))
print("decryption key: {0}" .format(d))
def e3p11a():
print("\nExercise 3, Problem 11a")
e = 13
n = 2881
d = generatePrivate(e,n)
print("decryption key: {0}" .format(d))
def e3p11b():
print("\nExercise 3, Problem 11b")
e = 7
n = 2881
d = generatePrivate(e,n)
print("decryption key: {0}" .format(d))
def e3p12():
print("\nExercise 3, Problem 12")
e = 13
n = 35209
d = generatePrivate(e,n)
print("decryption key: {0}" .format(d))
def e3p14():
print("\nExercise 3, Problem 14")
n = [1997,1999,2001,2002,2003,2004,2005]
phi = [0,0,0,0,0,0,0]
for i in range (0,len(n)):
phi[i] = eulerPhi(n[i])
print("phi({0}) = {1}" .format(n[i],phi[i]))
def e3pEC():
print("\nExercise 3, Extra Credit")
e = 13
n = 2881
d = generatePrivate(e,n)
text = "To be, or not to be- that is the question: Whether 'tis nobler in the mind to suffer The slings and arrows of outrageous fortune Or to take arms against a sea of troubles, And by opposing end them. To die- to sleep- No more; and by a sleep to say we end The heartache, and the thousand natural shocks That flesh is heir to. 'Tis a consummation Devoutly to be wish'd. To die- to sleep. To sleep- perchance to dream: ay, there's the rub!"
textEncoded = list(text.encode())
textEncrypted = []
for i in range(0,len(textEncoded)):
textEncrypted.append(encryptRSA(textEncoded[i],e,n))
textDecrypted = []
for i in range(0,len(textEncrypted)):
textDecrypted.append(decryptRSA(textEncrypted[i],d,n))
textDecryptedPT = bytes(textDecrypted).decode()
print("Original Text: {0}" .format(text))
print("Encoded Text: {0}" .format(textEncoded))
print("Encrypted Encoded Text: {0}" .format(textEncrypted))
print("Decrypted Encoded Text: {0}" .format(textDecrypted))
print("Decrypted Decoded Text: {0}" .format(textDecryptedPT))
part = "start"
while(part != "exit"):
part = input("Which question would you like to display? [11a, 11b, 12, 14, or EC]: ")
if(part == "11a"):
e3p11a()
elif(part == "11b"):
e3p11b()
elif(part == "12"):
e3p12()
elif(part == "14"):
e3p14()
elif(part == "EC"):
e3pEC()
elif(part == "all"):
e3p11a()
e3p11b()
e3p12()
e3p14()
e3pEC()
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1.版本:matlab2021a,我录制了仿真操作录像,可以跟着操作出仿真结果 2.领域:RSA_Hash算法 3.内容:基于RSA_Hash算法的文字加密系统,将文字解密到图像中并通过解密提取文字信息+仿真录像
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基于RSA_Hash算法的文字加密系统,将文字解密到图像中并通过解密提取文字信息.rar (21个子文件)
基于RSA_Hash算法的文字加密系统,将文字解密到图像中并通过解密提取文字信息
操作录像0035.avi 4.3MB
111.jpg 6KB
matlab
HashLSB_Steganography
image.jpg 255KB
BitHashing.m 595B
Picdecode.m 1KB
Picencode.m 1KB
Runme.m 463B
RSA_Encryption
generatePrivateRSA.m 881B
extEuclidAlgo.m 963B
generatePublicRSA.m 935B
RSA_Driver.m 2KB
encryptRSA.m 420B
primeFactors.m 1KB
decryptRSA.m 470B
eulerPhi.m 672B
generateRSAkeys.m 1KB
euclidAlgo.m 798B
rsa.py 4KB
RSA-Hash_Steganography
decodeHashRSA.m 570B
encodeHashRSA.m 608B
221.jpg 51KB
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