Python题库答案(1).zip

# 【问题描述】 # 从文件in.txt读取信息，文件里的单词中间由空格隔开 # 统计每个单词出现的次数，从大到小排序后输出到文件out.txt # 【输入形式】 # 文件里存储了多个单词，有重复，空格隔开 # 【输出形式】 # 从大到小输出单词及其出现的次数，次数一样的单词按字符串比较从小到大排序 # 【输入样例】in.txt文件里面的数据如下所示： # hello world python hello word file number file file # 【输出样例】out.txt文件里面的数据如下所示： # file 3 # hello 2 # number 1 # python 1 # word 1 # world 1 # text1 = open("in.txt","w") # text1.write("hello world python hello word file number file file") # text1.close # text1 = open("in.txt","r") # line = text1.readline() # # print(line) # listline = list(line.split()) # # # print(listline) # setlistline = set(listline) # numberlistline = {} # for i in setlistline: # numberlistline[i] = listline.count(i) # # print(numberlistline) # listnumberlistline = [] # for k,v in numberlistline.items(): #循环中的序列解包 # listnumberlistline.append([k,v]) # # print(listnumberlistline) # # 按购买金额降序 # for i in range(len(listnumberlistline)-1 ,0 ,-1): # for j in range(0,i): # if listnumberlistline[j][1] < listnumberlistline[j+1][1]: # listnumberlistline[j],listnumberlistline[j+1] = listnumberlistline[j+1],listnumberlistline[j] # # print(listnumberlistline) # # 按购买次数降序 # for i in range(len(listnumberlistline)-1 ,0 ,-1): # for j in range(0,i): # if listnumberlistline[j][1] == listnumberlistline[j+1][1]: # if listnumberlistline[j][0] > listnumberlistline[j+1][0]: # listnumberlistline[j],listnumberlistline[j+1] = listnumberlistline[j+1],listnumberlistline[j] # # print(listnumberlistline) # text2 = open("out.txt","w") # for i in range(len(listnumberlistline)-1): # text2.write(str(listnumberlistline[i][0])+' '+str(listnumberlistline[i][1])+'\n') # text2.write(str(listnumberlistline[len(listnumberlistline)-1][0])+' '+str(listnumberlistline[len(listnumberlistline)-1][1])) # text2.close # text2 = open('out.txt','r') # a = text2.read() # print(a) # text2.close import operator from os import close filename = "in.txt" filenameout = open("out.txt","w") fp = open(filename,"r") content = fp.read() fp.close() a = content.split() b = set(a) c = [] for i in b: c.append([i,a.count(i)]) c.sort(key=operator.itemgetter(0)) c.sort(key=operator.itemgetter(1),reverse=True) for i in c: print(i[0],i[1],file = filenameout) filenameout.close() print(c)