配置Struts2.0
基础配置
1）引入Struts必需的五个jar包。
2）修改WEB-INF下的web.xml文件，增加struts2的配置。
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
3）添加struts配置文件。 在WEB-INF/classes目录下，新建struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
</struts>
配置一个Action
1）首先新建一个登陆页面login.jsp
<body>
<s:form name="form1" action="login" >
<s:textfield name="username" label="username" ></s:textfield>
<s:password name="password" label="password" ></s:password>
<s:submit label="submit"></s:submit>
</s:form>
</body>
</html>
2）在我们已经建好的struts.xml中来配置登录的action。
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<package name="struts2" extends="struts-default">
<action name="login" class="test.LoginAction">
<result name="success" type="redirect">index.jsp</result>
<result name="input">login.jsp</result>
<result name="error">login.jsp</result>
</action>
</package>
</struts>
3）下面就来编写具体的action类
1package test;
2import com.opensymphony.xwork2.ActionSupport;
3public class LoginAction extends ActionSupport {
4 public String username;
5 public String password;
6 public String execute(){
7 if(!username.equals("admin")){
8 super.addFieldError("username", "用户名错误！");
9 return ERROR;
10 }
....
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配置Hibernate3.0
基础配置
