Chapter 1
1. The metric prefixes (micro, pico, nano, . . .) are given for ready reference on the inside front cover of the
textbook (see also Table 1-2).
(a) Since 1 km = 1 × 10
3
m and 1 m = 1 × 10
6
µm,
1 km = 10
3
m = (10
3
m)(10
6
µm/m) = 10
9
µm .
The given measurement is 1.0 km (two significant figures ), which implies our result should be
written as 1.0 × 10
9
µm.
(b) We calculate the number o f microns in 1 centimeter. Since 1 cm = 10
−2
m,
1 cm = 10
−2
m = (10
−2
m)(10
6
µm/m) = 10
4
µm .
We conclude that the fraction of one centimeter equal to 1.0 µm is 1.0 × 10
−4
.
(c) Since 1 yd = (3 ft)(0.3048 m/ft) = 0.9144 m,
1.0 yd = (0.91 m)(10
6
µm/m) = 9.1 ×10
5
µm .
2. The customer expects 20 × 7056 in
3
and receives 20 × 5826 in
3
, the difference being 24600 cubic inches,
or
24600 in
3
2.54 cm
1 inch
3
1 L
1000 cm
3
= 403 L
where Appe ndix D has been used (see also Sample Problem 1-2).
3. Using the given conversion fa c tors, we find
(a) the distance d in rods to be
d = 4.0 furlongs =
(4.0 furlongs)(201.168 m/furlong)
5.0292 m/rod
= 160 rods ,
(b) and that distance in chains to be
d =
(4.0 furlongs)(201.168 m/furlong)
20.117 m/chain
= 40 chains .
4. (a) Recalling that 2.54 cm equals 1 inch (exactly), we obtain
(0.80 cm)
1 inch
2.54 cm
6 picas
1 inch
12 points
1 pica
≈ 23 points ,
(b) and
(0.80 cm)
1 inch
2.54 cm
6 picas
1 inch
≈ 1.9 picas .
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