Microelectronics: Circuit Analysis and Design, 4th edition SOL...
1星 需积分: 48 155 浏览量
2019-02-24
16:11:51
上传
评论 1
收藏 147KB PDF 举报 
Microelectronics: Circuit Analysis and Design, 4
th
edition Chapter 1
By D. A. Neamen Exercise Solutions
______________________________________________________________________________________
Chapter 1
Exercise Solutions
EX1.1
3/2
exp
2
g
i
E
nBT
kT
−
⎛⎞
=
⎜⎟
⎝⎠
GaAs:
()
()
()
()
3/2
14
6
1.4
2.1 10 300 exp
2 86 10 300
i
n
−
⎛⎞
−
⎜⎟
=×
⎜⎟
×
⎝⎠
or
63
1.8 10
i
ncm
−
=×
Ge:
()
()
()
()
⎟
⎟
⎠
⎞
⎜
⎜
⎝
⎛
×
−
×=
−
30010862
66.0
exp3001066.1
6
2/3
15
i
n or
13 3
2.40 10
i
ncm
−
=×
______________________________________________________________________________________
EX1.2
(a) (i) cm
16
102×==
do
Nn
3−
()
4
16
2
10
2
10125.1
102
105.1
×=
×
×
==
o
i
o
n
n
p
cm
3−
(ii) cm
15
10==
ao
Np
3−
()
5
15
2
10
2
1025.2
10
105.1
×=
×
==
o
i
o
p
n
n
cm
3−
(b) (i) cm
16
102 ×==
do
Nn
3−
()
4
16
2
6
2
1062.1
102
108.1
−
×=
×
×
==
o
i
o
n
n
p
cm
3−
(ii) cm
15
10==
ao
Np
3−
()
3
15
2
6
2
1024.3
10
108.1
−
×=
×
==
o
i
o
p
n
n
cm
3−
______________________________________________________________________________________
EX1.3
(a) For n-type;
()
()
()
046.0
1026800106.1
11
1619
=
××
==
−
dn
Ne
μ
ρ
ohm-cm
(b)
()()
04.8175046.0
1
===Ε⇒Ε⋅= JJ
ρ
ρ
V/cm
---------------------------------------------------------------------------------------------------------------------------------
EX1.4
Diffusion current density due to holes:
()
16
1
10 exp
pp
p
pp
dp
JeD
dx
x
eD
LL
=−
⎛⎞ ⎛
−−
=−
⎜⎟ ⎜
⎜⎟ ⎜
⎝⎠ ⎝
⎞
⎟
⎟
⎠
资源评论
renleizznp2019-10-19垃圾，垃圾，浪费
malcolm_1102019-07-24只有第一章，骗子！
