单电源运放详解.pdf

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单电源运放详解
tVcc +Vcc R1 100kg2 O vcc/2 R2 C1 100kg 0.1uF INVERTING +vEc Gai二-R2R1 R3=R1|R2 Gin for minimum error due no to input bias curren Vont R3 NONINVERTING Gain= 1+ R2R1 Input Impedance= R1R2 2 vout for minimum errot due to input bias current R H2 INVERTING Gain=-R2/R1 R3=R1|R2 cIn for minimum error due R1 to input bias current -C youi RI P INVERTING svce Component values normalized to unity RinA 1 R|n日1 R3 TEC2 DB Pad Vout/Vin R3 0 000o 0.5 0.9 0.89 0977 0.794 0.93 07Q7 0 0.707 20 0.6667 000 06310 08549 5 0.562 050 0.5024 05000 0.500 000 4b 0403 98 0.330 5 02500 0.2512 04 02500 0.1bb 8 0.2000 01778 0108 5.5 016 0.100 16.90 0 9 008 0 9 007201 1806 0.1250 0.0714 08 01111106250 01000 0.055 25 00562 0.02979 00316 0.016 00100 000505 50 0.003 0.001586 60 0.0010 00005005 NONINVERTING cc Component values normalized to unity v酒 Necl Figure 6. Noninverting Attenuation NON NYERTING Component values normalized to unity 叫酯 vn R vaul VEr2 R3 ForR1〓R3andR2〓R4 +Yer Wout=(R2/R1)(Vin2-vin1 R1|R2=R3|R4 for minimum error cue cln1 RI to input bias current vit i 合Waut R R TcHE 4 +Vcc L〓R1R2*c1 C1 Vino H Vout R2 Vcc/2 R1 vET Lee ASSUMES VIn-AND Vin+ REFERENCED TO Vcc/2 R1=R3(matched R2= R4 (matched] R5=R6 Ncc Gain= R2/R1(1+ 2RS/R7K RE R3 R+ Weep ASSUMES WIN AND Vin+ REFERENGED TO Vec? R1=R3(matched R2=R4 matched Gain= R2R1 R- 点 SUMES VO- AND YIn卡 REFERENCED TO Veel2 Me? eOr R1〓R4( matcher R2=R3〔 matcher) sOir Gain=1+R1R2

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