python 将将json数据提取转化为数据提取转化为txt的方法的方法
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助。一起跟随小编过来看看吧
如下所示:如下所示:
#-*- coding: UTF-8 -*-
import json
import pymysql
import os
import sys
# 数据类型
# {
# "name": "score.networkQuality",
# "index": true,
# "view": "app/views/score/networkQuality.tmpl.html",
# "files": ["app/modules/controllers/score/networkQualityCtrl.js"]
# },
name = []
index = []
views = []
files = []
# "name": "monitored.monitored",
with open('C:\Users\sxf\Desktop\app-modules.json') as f:
for line in f:
try:
line.index("name")
# line = line.strip('')
pos = line.index(':')
name.append(line[pos+3:len(line)-3])
except ValueError:
pass
try:
line.index("true")
# line = line.strip('')
pos = line.index(':')
index.append((line[pos+2:len(line)-2]))
except ValueError:
pass
try:
line.index("view")
try:
line.index("name")
except ValueError:
pos = line.index(':')
views.append(line[pos + 3:len(line) - 3])
except ValueError:
pass
# ['app/modules/controllers/monitored/monitoredCtrl.js","app/modules/services/resources/resourcesService.j']
try:
line.index("files")
# line = line.strip('')
pos = line.index(":")
try:
i=0
str1 = ""
str2 = ""
str3 = ""
pos_comma = line.index(",")
str = line.split(',')
comma_count = line.count(',')
while i<=comma_count:
if i == 0:
# str[0] = str[0].strip('\n')
str1 = str[0][pos+4:len(str[0])-1]
elif i == 1 :
if comma_count == 1:
# str[1] = str[1].strip('')
str2 = str1+','+str[1][1:len(str[1])-3]
else:
str2 = str1 + ',' + str[1][1:len(str[1]) - 1]
elif i == 2 :
# str[2] = str[2].strip('\n')
str3 = str2+','+str[2][1:len(str[2])-3]
else:
pass
i = i + 1
if (comma_count == 1):
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