python 实现分组求和与分组累加求和代码
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2021-01-20
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python 实现分组求和与分组累加求和代码实现分组求和与分组累加求和代码
我就废话不多说了，大家还是直接看代码吧！
# -*- encoding=utf-8 -*-
import pandas as pd
data=['abc','abc','abc','asc','ase','ase','ase'] num=[1,2,2,1,2,1,2] df1=pd.DataFrame({'name':data,'num':num})
print(df1)
df1['mmm']=df1['num'] df2=df1.groupby(['name', 'num'], as_index=False).count()
print(df2)
df2.sort_values(['name', 'num'], ascending=[1, 1], inplace=True)
print(df2)
df2['sum']=df2.groupby(['name'])['mmm'].cumsum()
print(df2)
kk=df2.groupby(['name'],as_index=False)['num'].sum()
print(kk)
df3 = pd.merge(df2, kk, on='name', how='left',)
print(df3)
df3['ratio']=df3['sum']/df3['num_y'] df3.columns = ['name', 'num', 'mmm', 'sum','numsum','ratio'] print(df3)
df4=df3.groupby(['mmm'],as_index=False)['ratio'].mean()
print(df4)
运行：
name num
0 abc 1
1 abc 2
2 abc 2
3 asc 1
4 ase 2
5 ase 1
6 ase 2
name num mmm
0 abc 1 1
1 abc 2 2
2 asc 1 1
3 ase 1 1
4 ase 2 2
name num mmm
0 abc 1 1
1 abc 2 2
2 asc 1 1
3 ase 1 1
4 ase 2 2
name num mmm sum
0 abc 1 1 1
1 abc 2 2 3
2 asc 1 1 1
3 ase 1 1 1
4 ase 2 2 3
name num
0 abc 3
1 asc 1
2 ase 3
name num_x mmm sum num_y
0 abc 1 1 1 3
1 abc 2 2 3 3
2 asc 1 1 1 1
3 ase 1 1 1 3
4 ase 2 2 3 3
name num mmm sum numsum ratio
0 abc 1 1 1 3 0.333333
1 abc 2 2 3 3 1.000000
2 asc 1 1 1 1 1.000000
3 ase 1 1 1 3 0.333333
4 ase 2 2 3 3 1.000000
mmm ratio
0 1 0.555556
1 2 1.000000
Process finished with exit code 0
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