### 天大851初试资料 评分

n DATE NO 10p9m 3-0. molly n(kuno (4两)A02mm 70xo3 4、J60 0.03652o n(3 (80×2 DoDo moll n(2,B)=2,mB) n(2b)=22nB) c(=8)=盏n( 40c)=2(%)C()C(4D0m )C(5)=2C%92)=2.20ma B)c(K0)=7 4)= 0.4p mol 9k力取) k0这原利可C02-②上()b 为C(=)EAm 方时3E的 =30) A什为还剂时来分EbA)4=Dm ru-k .421+01 =0-m ∥=006∠ -3 h(Hu)=0.130310-0003muoc nwo cd,)2=0.07/5oul mAa3)三ABbx=D QIDE HENG b M(e)CB X/0 u DATE→抄用几nNO 7.)(A02HC7 CA/支M(CA)C比C)35x6.08xb4m0x2-0∞426 H A( DHDDCUHODXI3=40D0×BACD 3=00011 2(103x①0D3D分 3=5×678x0A0x10=D2483 2)从n+C22+16+=2n2+10(21+8h 702=于APCm0w=于 8、Dx01200Y1D=0DB子、m 2=G32D2 70=3从(CB)CDC)=4、2y0D203Dm Hu osn A(=640803022-=0gm OAam)A(H2=D2×2(12-00(8=D0D468m1=nA0 1()=D4①一)%长后两1) h 54mm=人a× 10-5 CAb loDH t NaoH h(ci,cooH)=h waoH)=0. 30/8x 28-60x103-0. 00863) mu/ 00863/Xb0D /0 xD=42 第 +ka=26202 < 3 的12= 30 2==40 =4/ka2 kby= ka/k 么(2) Nih2Ch2C0u入水后一 Nhb, Ch CoDH NcmH+业内bm4一k=包 M,Ch H+ NC# Coo 1a→k ka=25×0 Ho bi=ta pola:A tch Co=A CH Co QIDES HENG 上 DATE NO 强以)DkAb 如从某强项A(实证出副 H求 HUH PBE[=Hn+(m 1A分BLA252+ 3)AaC气(CABE【HC1+[0]=m 以BA(ABEA=Ee[Cotn )()NDN+)=H )A5(5)既【]+t5+1m=D0H 5) aHD 2)8h(+10=L2+LH Het: PB: Tec)+LoH 3=L+o) B么一元),(1+9,F+h0三H+B +0102+0H P82140+]=m+ 总P[=0+LAC+B0 2)① PHC PBE:L+oH]= e Alb pos PBE: [xpo 3+27po/3+Loh 2 Cr0J+Upa. 总D10+DP1=D0++1D3+[o 3)①m(A、的0)PBE:DM+D0=H QIDES HENG 图不用小准 )对码 DATE NO ⊙AaH△. MBE. LOH]=C+ CBE: LNa)+ IWJ=Tok .PBt: LNo+ 7H J- od 3 B-PBt Wa J+ UHy tC]=ton J a产 A8:C+=H+7+R+四购,C6=D E:L+的!=[h9a41+3tp]+3P21to PB:C2+D均P]+[=Up+321+乙o THF)+ThsD =CoH ]+tAc) calhau) 0(2=-1m43m”m=18、c2号=38m MBT: CH'=C+ Lord CB:]=o]+2s2 ISo=C →PBE:U=[0+tso=o+2C +2C CB5s2=536032m4CD+1>10mo 最简式6]=26=070m 324D 2).C= D 0m0(L2ka=18x10 Cka>20且 c/Fa 7s D]=Cka=01480 3 =I-D)/ mol-L =230 kb°=10° 00= 0-80m0- 0-22 ckb>nEw B C/b>f0:- 700 )=crb=358x10-6 poH=54s =-8 QIDESHEI (4).C=03sm(ka DATE NO NH2AC NOz ka:5-6x10 3阳十磊减D=B)+6 dec ka=k8xo-s A陆2力 CAA=35x56x0=0>100 一N=06c3=03m 如/b>yD .TH J=kaka =20 CCA应hB)B3(+多戒() N+上a=5.6x0=0 Ba=5.8x0° aka >okw UAH+ J= [HBi J=C=0-030- kaA-kb比币言信小M、H壁不计,A占优 PakQ=680=570 N一+N的 pH=24 计 0种一元言A上=3 rias Ca/ku )m 81上=5800c“k。2x 时=A+。CA=13403 NH+ H eMh 人H n0了0m3b-m3 N1冲 D-02 P 03 00]=比480-=0mL 3>2010 可以用简式=-: b=D2>)020 A中液时=A 16=4 A0220的C=0022 6UH+1 HAC Cb=上 =8×10 LoH .501s) pH: pka OIDESHENG 18×02 x10 0 DATE NO 7(1)CkA=0x0>23可面海 0-| A NaDk NaDH+ChbCCoDH CthacooNat hho =k0/ka=210x02 b =(9x03m =14-10H=228 △遍剂一计算奖克不跳位F亲到义运示小刻(多面计 像+: ,0=0123122=1p:多 g5~870购欣 12(k=3.2D6/03可b反 A o..- Hu HOct CNH+=P∠他(N 5PD泵对加bCh(k=mnkb3 ka(a>)0o且Cn/ka> D=4(=30(pH4 pp+30 6 01 n 3 61-4山一 12)(k=03)03不重区通交 H Eax. 3-9x k Co: D-a nol t DATE NO owo Cook Waoh Ck+0k2=39x/0 均/2=2、6x0 sp.5, Cb kb, >loko 2 Co/kb 23m )==1305m8=14-po= 花离80~870(过)可兰防献 )ka(a=01<103、可 8.+NN边 g8 起点,A则液P时=p-x- D17=2 D.1y2=292 正]=0,/202=2 2>02+0 =430 6-x~430 3Cka=1x10-3>10 Ca=1×10 /0 角两考人直海于 CEn3=0+2=10-8不可题据通 Faa =/0->10 H3B toH=HB+ o ka 179()=) hB:向反 Cukazz boku C=0> lokal 最式的头210平 HB+ bH= HB+ h o ka2 第)5C(B)=D3mbm(=30 Cka3>100C=03>20ka [6)=JA2k=3xB=0 QlD HENG DATE NO 10.①C032 H(2 ⊙C )-Hos ①CB AcO 0/x2}-3 2+H C((0) H++三 0.y84+ ③/C3+月=H C(10s) 3 H03+H+HsM H2++2 CH)=0/(2.8-180 ③C(o3) D5×(4+ C(h)=(×(280-4 2△ ④H++e=h C( 3 0s×/B3 ①c(2)=22+ a(H2y)=Dx(3-12) x 24 0+H+=H +0+÷Ba A=1202m 6B)=03m0248B2)x034D=DCa C8%y:42 m0(23)=03m×12.02x10-3y/06、0 H+0→H 入 4+H-h0 P1M:427md ))01=2) b QIDESHEN

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