Signals and Systems 2nd Ed. Haykin [Solutions_Manual]
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2013-10-23
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1
CHAPTER 1
1.1 to 1.41 - part of text
1.42 (a) Periodic:
Fundamental period = 0.5s
(b) Nonperiodic
(c) Periodic
Fundamental period = 3s
(d) Periodic
Fundamental period = 2 samples
(e) Nonperiodic
(f) Periodic:
Fundamental period = 10 samples
(g) Nonperiodic
(h) Nonperiodic
(i) Periodic:
Fundamental period = 1 sample
l.43
(a) DC component =
(b) Sinusoidal component =
Amplitude =
yt() 3 200t
π
6
---+
cos
2
=
9 200t
π
6
---+
2
cos=
9
2
---
400t
π
3
---+
1cos=
9
2
---
9
2
---
400t
π
3
---+
cos
9
2
---
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资源评论
xxxRXxxx2014-05-30注意这本书书答案
xudianhui2014-09-22非常不错的资源- qq1195432132014-12-06The answer is not complete right.
