C++ 兔子问题 水仙数 9*9乘法矩阵 石头剪子布

#include <iostream> using namespace std; void main() { char i,I,S,R,P,r,s,p; char num1,num2; cout<<"欢迎您来玩石头剪子布游戏！"<<endl<<"(离开请输入:i(I)，石头：r(R),剪子:s(S),布:p(P))"<<endl; loop1: cout<<"现在请玩家1输入:"<<endl; cin>>num1; //if(num1=='i'||num1=='I') //{ switch(num1) { case 'i': case 'I': cout<<"您将结束游戏！"<<endl; goto jieshu; break; case 'r': case 'R': cout<<"您输入的是：石头"<<endl; break; case 's': case 'S': cout<<"您输入的是：剪子"<<endl; break; case 'p': case 'P': cout<<"您输入的是：布"<<endl; break; default: cout<<"输入错误，请重新输入"<<endl; goto loop1; } loop2: cout<<"现在请玩家2输入："<<endl; cin>>num2; switch(num2) { case 'i': case 'I': cout<<"您将结束游戏！"<<endl; goto jieshu; break; case 'r': case 'R': cout<<"您输入的是：石头"<<endl; break; case 's': case 'S': cout<<"您输入的是：剪子"<<endl; break; case 'p': case 'P': cout<<"您输入的是：布"<<endl; break; default: cout<<"输入错误，请重新输入"<<endl; goto loop2; } if((num1=='r'&&num2=='s')||(num1=='s'&&num2=='p')||(num1=='p'&&num2=='r')||(num1=='R'&&num2=='S')||(num1=='S'&&num2=='P')||(num1=='P'&&num2=='R')) { cout<<"玩家1 赢了！"<<endl; } else if((num2=='r'&&num1=='s')||(num2=='s'&&num1=='p')||(num2=='p'&&num1=='r')||(num2=='R'&&num1=='S')||(num2=='S'&&num1=='P')||(num2=='P'&&num1=='R')) { cout<<"玩家2 赢了！"<<endl; } else { cout<<"玩家1 和 玩家2 平手！"<<endl; } cout<<"是否继续玩？(y/n)"<<endl; char panduan; cin>>panduan; if(panduan=='y'||panduan=='Y') { goto loop1; } jieshu: ; /*}*/ /*else if(num1=='i'||num1=='I') { cout<<"按Enter键结束"<<endl; }*/ }