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Switching Power Supply
Fundamentals
To start, we will review the basic operation of switching power supplies as a basis for understanding the
selection criteria for the external components needed for optimum performance of the power supply.
Despite the increasing popularity of monolithic switching regulators, linear regulators still dominate the
market. Inexpensive and easy to use, these regulators can be found almost anywhere. Even so,
understanding the differences between different types of linear regulators can be key to making the best
use of this ubiquitous component.
1-2
2
© 2006 National Semiconductor Corporation
A DC-DC Converter is Just a….
+
-
1.24K
1.24V
V
REF
12V
10.8K
5 V
Any regulated power supply, including a switching regulator, can be considered simply as an amplifier with
relatively low output impedance. The input to the amplifier is a fixed reference and the output is regulated
to a value set by the gain of the amplifier to the reference voltage and is ideally independent of the supply
(source) voltage. For a linear regulator, the output voltage must always be less than the source voltage but
in the case of a switching regulator, the output voltage can be higher (boost), lower (buck) or inverted
compared to the source voltage. All the theory you remember (or have forgotten) from control systems
classes in college applies to linear and switching regulators.
In the case above, the output voltage is higher then the supply voltage. Normally this would be impossible,
but if the output stage of the amplifier is a DC-DC boost regulator (a switcher), then this is possible.
In addition to producing output voltages that are outside of the range of the source voltage, switching
regulators are available in a wide range of architectures. During this part of the presentation, we will be
reviewing switching power supply fundamentals followed by a look at different switching architectures and
their applications based on these concepts.
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EA output
Oscillator
ramp
SW output
3
© 2006 National Semiconductor Corporation
Basic PWM DC-DC Converter
Compared to many conventional amplifiers, a DC-DC converter is merely an amplifier with a high power
output stage. The Error Amplifier (EA) compares some proportion of the output voltage (determined by the
feedback network) with the reference voltage and generates an error output. This error voltage is
compared to a fixed amplitude ramp voltage generated by the local oscillator and when the EA output
matches the voltage on the oscillator ramp, a Reset turns off the latch. As the error voltage increases the
duty cycle of the latch will increase as shown below. In steady state conditions the EA output will adjust
itself so that the duty cycle produces the reference voltage at the FB pin - thus the correct output voltage.
With light loads, skip cycling can occur when the EA output is so low that the Reset stays high and
prevents the set signal from turning on the latch. All PWM converters work in this basic manner.
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4
© 2006 National Semiconductor Corporation
Step-Down Buck Regulator
V
DIODE
Input
Capacitor
Switch
Circulating
diode
Inductor
Output
Capacitor
T
PWM
OUTPUT
SWITCH
NODE
VOLTAGE
V
DIODE
Control
T
ON
T = 1/f
V
IN
V
IN
V
OUT
V
OUT
The buck regulator sends the output of the PWM comparator to the control switch. This results in a voltage
waveform at the SWITCH NODE which has an average value of V
OUT
. The Inductor and output capacitor
create a two pole low pass filter such that a DC voltage with only a relatively small ripple appears at the
output.
The duty cycle, D, is defined as T
ON
/T, and
V
OUT
=V
IN
*D.
This is the same equation as one would use to calculate the average value of a square wave with a
magnitude of “V
IN
”, a period of T and a duration of “T
ON
”.
The diode allows a path for the inductor current to flow or circulate when the control switch opens.
The buck regulator (and its variants) is the only topology that has a direct connection between the input
and the output when the control switch is on.
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5
© 2006 National Semiconductor Corporation
Buck Calculations for Inductance
• Need to know V
IN
, V
OUT
, I
OUT
, Switch resistance, operating
frequency, and diode drop
• Next calculate D
• We calculate
'
I where:
• And then inductance:
DSWIN
DOUT
V+V-V
V+V
T
Ton
D
f
DVVV
I
L
OUTSWIN
'
Rule of thumb:
',d
I
OUT
x 0.3
For a given set of performance parameters, the first component to select is the inductor value since this will
determine all the currents in the other components.
There are a number of ways to determine which inductance value is optimal for your circuit and the method
described above is our recommendation for general everyday use. It is based on using a current ripple
ratio (the ratio of the average inductor current to the total swing of the current during a switching cycle) of
0.4 for load currents up to 2A, and a ratio of 0.3 for load currents in excess of 2A. This produces a good
tradeoff between inductor size, output voltage ripple (produced by the ripple current flowing through the
capacitor ESR), and peak currents in the external components.
On occasion there may be reasons to increase or decrease the inductance value. The inductance value is
a major factor in determining stability of the control system. Decreasing the inductor value may allow for a
smaller size inductor. Increasing the value may allow for a cheaper output capacitor. Increasing the value
reduces peak currents and may allow you to achieve more output current from a cheaper switcher. Lastly,
Purchasing may be telling you to use up inventory from projects which are not selling as fast as they like.
Note: Since these equations were originally developed, capacitor technology has improved significantly.
Capacitors with very low ESR are easily available. This technology development may allow you to
decrease the inductance (increase ripple) beyond the guidelines above while still maintaining low output
ripple voltage.
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- shlll2016-08-29很全面,很好用,谢谢分享.
tellu0551
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