php ajax 实现局部刷新简单例子(超简单化)
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-
8" />
<title>无标题文档</title>
</head>
<script type="text/javascript" src="fun.js"></script>
<script type="text/javascript" src="jquery-1.3.1.min.js"></script>
<body>
<div id="test1">用户 GM</div>
<div>你有未读消息(<span id="count" ></span>)条</div>
</body>
</html>
fun.js
代码如下
function historyLotteryCode_1(){
$.ajax({
type: 'POST',
url : 'ajaxReturn.php',
data: "userid=12",
success: function(data){
alert(data);
var partn = /<script.*>.*<\/script>/;
if( data == 'empty' && partn.test(data) ){return;}
eval_r("data="+data);
document.getElementByIdx_x("count").innerHTML=data.count;
setTimeout(historyLotteryCode_1,5000);
}
});
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